sandramac
asked on
Formula Help
Hello All, I have the formula below, I am trying to figure out a way to code it so if E14=0, then in the formula, make E14=.01 (formula b), if E12=0 then formula C, if both E14 and E12 are 0, then formula D
((((6.11*10*(7.5*E14/(237. 7+E14))/(6 .11*10*(7. 5*E12/(237 .7+E12))))
)))*100
Formula B
((((6.11*10*(7.5*.01/(237. 7+.01))/(6 .11*10*(7. 5*E12/(237 .7+E12))))
)))*100
Formula C
((((6.11*10*(7.5*E14/(237. 7+E14))/(6 .11*10*(7. 5*.01/(237 .7+.01))))
)))*100
Formula D
((((6.11*10*(7.5*.01/(237. 7+.01))/(6 .11*10*(7. 5*.01/(237 .7+.01))))
)))*100
((((6.11*10*(7.5*E14/(237.
)))*100
Formula B
((((6.11*10*(7.5*.01/(237.
)))*100
Formula C
((((6.11*10*(7.5*E14/(237.
)))*100
Formula D
((((6.11*10*(7.5*.01/(237.
)))*100
Basically for each one, instead of
E14
You get the value from
IF(E14 = 0, 0.01, E14)
so that when E14 is non-zero, it is still E14, but if it is zero, you get 0.01
E14
You get the value from
IF(E14 = 0, 0.01, E14)
so that when E14 is non-zero, it is still E14, but if it is zero, you get 0.01
ASKER CERTIFIED SOLUTION
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= ((((6.11*10*(7.5*IF(E14=0,
Change all E14 to 0.01 for E14 = 0, (this formula contains 2 E14)
Change all E12 to 0.01 for E12 = 0, (this formula contains 2 E12)
Thus, the formula is
= ((((6.11*10*(7.5*IF(E14=0, 0.01,E14)/ (237.7+IF( E14=0,0.01 ,E14)))/(6 .11*10*(7. 5*IF(E12=0 ,0.01,E12) /(237.7+IF (E12=0,0.0 1,E12))))) )))*100
Change all E12 to 0.01 for E12 = 0, (this formula contains 2 E12)
Thus, the formula is
= ((((6.11*10*(7.5*IF(E14=0,
Or even a few characters less, though with logic a trifle harder to see:
=IF(E14=0,1/23771,E14/(237 .7+E14))/I F(E12=0,1/ 23771,E12/ (237.7+E12 ))*100
=IF(E14=0,1/23771,E14/(237
)))*100