dropdownlist text field format

hey guys, i have a dropdownlistbox and i am pulling information from a database,

i want to display information like this in the list


here is my c# code which display only the name and the ID number has a value

        ddIndentityNumber.Items.Add("List of drivers names:");
        ddIndentityNumber.DataSource = D.Return_driver();
        ddIndentityNumber.DataTextField = "name";
        ddIndentityNumber.DataValueField = "indentity_number";

please some one show me how to join the name with the surname?
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Imran Javed ZiaConsultant Software Engineer - .NET ArchitectCommented:
you have to change it in datasource, DataTable or Object List
if you are using Data Table then use computational Column and if you are using objects the add a new property wich concatinate the other two.
JCWEBHOSTAuthor Commented:
yes, i am using datatable, can you please show me how to concatinate? in C# code?
Pratima PharandeCommented:
you are getting data from databas
ethen change the query like this

Select name + '(' + surname + ')' as name from tablename

so that you will get data in name column itself no need to change .netcode
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JCWEBHOSTAuthor Commented:
i do not want to mess around with the query.
Pratima PharandeCommented:

 you want to show two data in a dropdownlist, you can combine two columns into 1 column and assign to the DataTextField
see the example

daAdapter = new SqlDataAdapter("SELECT course_type, course_num FROM tbl_course_offerings WHERE..........",con);
dcolFullCourse.ColumnName = "FullCourse";
dcolFullCourse.DataType = System.Type.GetType("System.String");
dcolFullCourse.Expression = "course_type + ' ' + course_num";
ddlCourse.DataSource - dsCourse.Tables["Course"].DefaultView;
ddlCourse.DataTextField = "FullCourse";
ddlCourse.DataValueField = "course_num";
JCWEBHOSTAuthor Commented:
can i use textformatstring?
Pratima PharandeCommented:
Imran Javed ZiaConsultant Software Engineer - .NET ArchitectCommented:
You can use following as:

DataTable dt = D.Return_driver();
dt.Columns.Add("Newname", System.Type.GetType("System.String"), "FirstName+'('+SirName+')'");
ddIndentityNumber.DataSource = dt;


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JCWEBHOSTAuthor Commented:
Works great!!!
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