PHP Preg_replace with a * in the pattern

Hello experts.

I have a small bit of code...

ix="3,*"
and i am trying to do a simple preg_replace so that it becomes
ix="3,3"

Basically whatever the first item is i want it to replace the star.
I think the star is causing me issues as i cant get anything to work.

Any help would be gratefully accepted ...

thanks



handypamAsked:
Who is Participating?
 
Beverley PortlockCommented:
The pattern is too general - try this

     $find[$i]='#ix="([0-9]*),(\*)"#';

"Any more help would get a huge :D from me"

I like hugs, but I guess I'll just have to settle for any points that come my way......
0
 
Beverley PortlockCommented:
Escape the * with a \ and always do your patterns in single quotes, not double quotes otherwise you wind up escaping the escape characters as well and regexes look bad enough to start with.

$pattern = '3,\*';

0
 
Beverley PortlockCommented:
Here you go, a better example
<?php

$pattern = '#(3),(\*)#';

$data = "Here is a test 3,* string";

echo  preg_replace( $pattern, '$1,$1', $data );

Open in new window


produces

Here is a test 3,3 string
0
Cloud Class® Course: MCSA MCSE Windows Server 2012

This course teaches how to install and configure Windows Server 2012 R2.  It is the first step on your path to becoming a Microsoft Certified Solutions Expert (MCSE).

 
handypamAuthor Commented:
Thank you for your help so far.
The code works in isolation but you look at this test
It really does strange things to the string....

Any more help would get a huge :D from me... thanks in advance

<?php
	$test = 'test test ix="2,*" test test ix="3,*" test test ix="4,*" test test';
		
	$i=0;
	$find[$i]='#ix="(.*),(\*)"#';
	$replace[$i]='ix="$1,$1"';
	
	echo "<br>Before:".$test;
	
	$t = preg_replace($find, $replace, $test);
	echo "<br>After:".$t;	

?>

Open in new window

0
 
Beverley PortlockCommented:
Oh - it was a HUGE :D not a HUG..... I misread it.

My apologies.....

:-O

0
 
handypamAuthor Commented:
Hurray it works

Faith in mankind = RESTORED!

Hugz + points
0
 
Beverley PortlockCommented:
Glad you're sorted. Thanks for the hugz as well as the points

:-D

One additional note - regex is greedy and will match as much as possible to a pattern like .* but you can tell it not to be greedy by using .*? so in your pattern I could have used

$find[$i]='#ix="(.*?),(\*)"#';

but if that test is always a number then it is safer to be specific which is why I replaced .* with [0-9]*
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.