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PHP using preg_replace to remove form tags and everything in between

Using PHP I want to remove a form from a string that contains html - Here is the php code I have been trying to use but it doesn't work. Any ideas?

$html = "<form ... </form>"

$pattern = "/<form(.*?)<\/form>/i";
$html = preg_replace($pattern,"",$html);

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codeflux

You're missing a semicolon.

<?php
$html = "before <form blah blah blah </form> after";
$pattern = "/<form(.*?)<\/form>/i";
$html = preg_replace($pattern,"",$html);
print "$html\n";
?>

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codeflux

(semicolon on the first line, btw - the one declaring $html)

dnotestine

ASKER

Thanks - the semicolon I forgot but was just for the comment here. The actual code in $html is:

<form action="http://www.artechchurchinteriors.com/portfolio/portfolio_zip_email.php" method='POST' name='hidden_email_form'>
<input type='text' id='email' name='email' value='enter email address to email list' size='35' onClick="SelectAll('email');" />  
<input type='hidden' name='hidden_html' id='hidden_html' value='' />
<input type='submit' name='submit' value=' Email Now ' />
</form>

-----------------

$html = preg_replace($pattern,"",$html);
print "$html\n";

Does not take out the Form :-(

dnotestine

ASKER

$pattern = "/<form(.*?)<\/form>/i";
$html = preg_replace($pattern,"",$html);

ASKER CERTIFIED SOLUTION

Terry Woods

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See answer

Terry Woods

The "s" pattern modifier allows the . wildcard to match newlines

Terry Woods

Note that the round brackets are unnecessary too...

$pattern = "/<form.*?<\/form>/is";