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How to return the matched string in Java?

Hi,
I have the following code:

      if ((buff.matches("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests"))) {
                	    FileLine = $1;
                   }

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As you may guess this does not work correctly.

I want to return the matched string from this code and assign it to FileLine.

How can I do it?

Thanks,

CEHJ

Try

FileLine = buff.group(1);

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CEHJ

('buff' would have to be of type Matcher)

for_yan

if myString is your string where you are looking for the pattern, this is how you print all matches:

Pattern p = Pattern.compile("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests");
Matcher m = p.matcher(myStrting);
while(m.find()){
String s1 = s.substring(m.start(),m.end());
System.out.println(s1);
}

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CEHJ

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Tolgar

ASKER

@ CEHJ:

What should I make to this code to make it compile?

    		   java.lang.String buff = null;
               while (in.hasNextLine()) {
            	   buff = in.nextLine();
                   if ((buff.matches("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests"))) {
                	    FileLine = buff.group(1);
                   }
               }

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Thanks,

CEHJ

What type is 'buff' - String or Matcher?

CEHJ

Doh - it's String ;) If you're looking linewise, you'll find the last code i posted is simpler

CEHJ