How to return the matched string in Java?

Hi,
I have the following code:

             
      if ((buff.matches("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests"))) {
                	    FileLine = $1;
                   }

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As you may guess this does not work correctly.

I want to return the matched string from this code and assign it to FileLine.

How can I do it?


Thanks,

TolgarAsked:
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CEHJCommented:
Try
FileLine = buff.group(1);

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0
CEHJCommented:
('buff' would have to be of type Matcher)
0
for_yanCommented:
if myString  is your string where you are looking for the pattern, this is how you print all matches:

  Pattern p = Pattern.compile("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests");
            Matcher m = p.matcher(myStrting);
        while(m.find()){
            String s1 = s.substring(m.start(),m.end());
   System.out.println(s1);
}
0
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CEHJCommented:
If  'buff' is a String, then it's potentially simplifiable to
buff = buff.replaceAll("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests.*", "$1");
System.out.println(buff);

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0

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TolgarAuthor Commented:
@ CEHJ:

What should I make to this code to make it compile?

    		   java.lang.String buff = null;
               while (in.hasNextLine()) {
            	   buff = in.nextLine();
                   if ((buff.matches("<a.*?href=['\"](http://.*?)['\"].*?>.*mytests"))) {
                	    FileLine = buff.group(1);
                   }
               }

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Thanks,
0
CEHJCommented:
What type is 'buff' - String or Matcher?
0
CEHJCommented:
Doh - it's String ;) If you're looking linewise, you'll find the last code i posted is simpler
0
CEHJCommented:
:)
0
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