bit conversion
public class BinDec{
public static void main(String argv[]){
System.out.println(Integer
System.out.println(Integer
}
}
I ran above program from link
http://www.jchq.net/certkey/0503certkey.htm
got output like
3
1000000
I did not understand how I got this output.
Any ideas, resources,sample code,links, highly appreciated. thanks in advance.
public static void main(String argv[]){
System.out.println(Integer
System.out.println(Integer
}
}
I ran above program from link
http://www.jchq.net/certkey/0503certkey.htm
got output like
3
1000000
I did not understand how I got this output.
Any ideas, resources,sample code,links, highly appreciated. thanks in advance.
SOLUTION
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ASKER
>>>In the first case you parse integer written as 11 in binary system.
11 in binary system is 3
In toString(64,2) case it in fact says present number 64 in binary system
why there is " " for 11 where as not present for 64.
where it says present number 64 in binary system. please advise
11 in binary system is 3
In toString(64,2) case it in fact says present number 64 in binary system
why there is " " for 11 where as not present for 64.
where it says present number 64 in binary system. please advise
ASKER CERTIFIED SOLUTION
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To access this solution, you must be a member of Experts Exchange.
11 in binary system is 3
In toString(64,2) case it in fact says present number 64 in binary system
and that would be 1000000
So the output looks quite understandable