The question is:
A stone (m =0.35[kg]) is whirled in a vertical circle attached to a string of length r =95[cm].
At the exact top of the path the tension in the string is 3 times the stone's weight.
What is the stone's speed at this point?
I know the follow equations help me:
v = f( 2(pi)(r) / t ) where f is a frequency (usually given, but here not)
a[c] = (v)^2 / r which gives me the centripetal acceleration.
My issue is I don't know any other way using what's given to find a time which (I think) is needed to solve this problem. Any guidance is much appreciated.