regex second to last

given a url
http://bla.com/ccc/bbb/cce/ded/file.html

I need file returned however if the url is

http://bla.com/ccc/bbb/cce/ded/
I need ded returned.

This is what I have so far which only works for first case

m/^.*\/([^.]*)/
NewtonianBAsked:
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käµfm³d 👽Commented:
Is this what you're after:
$url = "http://bla.com/ccc/bbb/cce/ded/";

$url =~ m#([^/]+)/([^/]+\.[^/]+)?$#;

if ($2) {
    print $2;
}
else {
    print $1;
}

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0
wilcoxonCommented:
This should be a little more concise...

$url =~ m{/([^/]+)/?$};

print $1, "\n";
0
NewtonianBAuthor Commented:
kaufmed: that almost works but i don't want .html

wilcoxon, i could not get that working
0
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wilcoxonCommented:
I'm not sure why you couldn't get it to work.  Here's a small script demonstrating that it works for both of your sample URLs.
#!/usr/local/bin/perl

my @urls = (
'http://bla.com/ccc/bbb/cce/ded/file.html',
'http://bla.com/ccc/bbb/cce/ded/',
);

foreach my $url (@urls) {
    unless ($url =~ m{/([^/]+)/?$}) {
        warn "could not parse URL $url - skipping";
        next;
    }
    print "$url  =>  $1\n";
}

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NewtonianBAuthor Commented:
hey wilcoxon please see comment above i don't want .html if its a file name just the name before .
thanks!
0
wilcoxonCommented:
Okay.  Here's a corrected version.

It will return the last directory if no file given or the base filename (without extension).
#!/usr/local/bin/perl

my @urls = (
'http://bla.com/ccc/bbb/cce/ded/file.html',
'http://bla.com/ccc/bbb/cce/ded/',
);

foreach my $url (@urls) {
    unless ($url =~ m{/([^/]+?)(?:/|(?:\.\w+)?)$}) {
        warn "could not parse URL $url - skipping";
        next;
    }
    print "$url  =>  $1\n";
}

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NewtonianBAuthor Commented:
jackpot wilcoxon thanks a lot
0
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Regular Expressions

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