asked on

preg_match_all expression help

Hi experts

I have regular expression for in my pregmatch below.
What i am trying to do it to add the <br/> to the expression so that i can match on that aswell to produce the follow

1:Stop!
2:In the name of love?
3:Before you<br/>
4:break my heart

But as you guessed I CANT DO IT :( urghhhhhhhh

can anyone help?

:D

$paragraph = "Stop! In the name of love? Before you<br/>break my heart";
preg_match_all("# ?([a-z ]+[\.\?!])#i",$paragraph,$sentance);

Open in new window

ASKER CERTIFIED SOLUTION

shanikawm

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

noam_dz

preg_split("/([.?\n])/", $paragraph, -1, PREG_SPLIT_DELIM_CAPTURE); or something like that. If I understand your question.

SOLUTION

ollyatstithians

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

ollyatstithians

Sorry, the delimiters are missing. This:

<?php
header('content-type: text/plain');
$paragraph = 'Stop! In the name of love? Before you<br/>break my heart';
$sentence = preg_split('%(?:(?<=[!?])|(?<=<br/>)) ?%i', $paragraph);
var_dump($sentence);

Open in new window

returns:

array(4) {
  [0]=>
  string(5) "Stop!"
  [1]=>
  string(20) "In the name of love?"
  [2]=>
  string(15) "Before you<br/>"
  [3]=>
  string(14) "break my heart"
}

Open in new window

noam_dz

you can also try this simple regex [\w\s]+[!\?]?

or more php-ish /[\w\s]+[!\?]?/

/([\w\s]+)[!\?]?/ -> with capturing groups

ollyatstithians

noam_dz: That regex does not detect the <br/> as requested in the question.

handypam

ASKER

thanks for your help experts....