kadin
asked on
Geometry with Algebraic equation
I try different ways to do this but the answer I get is different than the book answer.
The book answer is 15 degrees. Can someone tell me what I am doing wrong? Thanks.
4x+55 =
-55 = -55
4x = -55
4x/4 = -55/4
x = 13.75 deg.
10x-85 =
+85 = +85
10x = 85
10x/10 = 85/10
x = 8.5 deg.
4x+55 = 10x-85
+85 = +85
4x+85 = 10x
-4x -4x
85 = 6x
85/6 = 6x/6
deg. 14.2 = x
geo01.jpg
The book answer is 15 degrees. Can someone tell me what I am doing wrong? Thanks.
4x+55 =
-55 = -55
4x = -55
4x/4 = -55/4
x = 13.75 deg.
10x-85 =
+85 = +85
10x = 85
10x/10 = 85/10
x = 8.5 deg.
4x+55 = 10x-85
+85 = +85
4x+85 = 10x
-4x -4x
85 = 6x
85/6 = 6x/6
deg. 14.2 = x
geo01.jpg
ASKER CERTIFIED SOLUTION
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You have ANGLE_P = 4x+55 and ANGLE_Q = 10x-85
>> 4x+55 = 10x-85
So you are saying that ANGLE_P = ANGLE_Q
This would be a true statement if, for example, ANGLE_P were <1 and ANGLE_Q were <4 (since alternate interior angles are equal).
>> 4x+55 = 10x-85
So you are saying that ANGLE_P = ANGLE_Q
This would be a true statement if, for example, ANGLE_P were <1 and ANGLE_Q were <4 (since alternate interior angles are equal).
>> but I did not think to add the two equations together.
You should set up symbols, and then state what you know. For example:
ANGLE_P + ANGLE_Q = 180 (if ANGLE_P were <1 and ANGLE_Q were <3)
Then you just plug in and solve.
You should set up symbols, and then state what you know. For example:
ANGLE_P + ANGLE_Q = 180 (if ANGLE_P were <1 and ANGLE_Q were <3)
Then you just plug in and solve.
ASKER
That's a good idea. Thanks for that.
ASKER