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Find peaks in sine curve

Posted on 2011-04-19
Medium Priority
Last Modified: 2012-05-11
What is the best way to find the peak points on a sine or sine-like curve?
Attached is some example data.
I'm not looking for code that reads in data, assume the data is in an array.

Question by:allelopath
  • 2
LVL 47

Expert Comment

ID: 35428730

I think you need to have some condition - say you want to find certain number of highest maxima or you want
to find all maxima higher than some value

Then you can scan all the pioints and find all locations where
 (value[j-1]<value[j] && value[j+1]<value[j])
then you storea all such values (both x and values for each point)  say in the ArrayList
and after you collected all of them analyze all these points
using the condition specified - and end up with the list of peaks you need.

LVL 47

Accepted Solution

for_yan earned 2000 total points
ID: 35429008

This is the code:

import java.io.DataInputStream;
import java.io.FileInputStream;
import java.util.ArrayList;
import java.util.StringTokenizer;
public class SineData {

    ArrayList x;
    ArrayList y;

    ArrayList peaksx;

    ArrayList peaksy;

    public SineData() {

         x = new ArrayList();
            y  = new ArrayList();;

            peaksx  = new ArrayList();;

           peaksy  = new ArrayList();;

        try {

            DataInputStream in = new DataInputStream(new FileInputStream("C:\\temp\\test\\sinedata.txt"));
            String buff = null;
            while((buff=in.readLine()) != null){

                StringTokenizer t = new StringTokenizer(buff);
                x.add(new Double(t.nextToken()));
                y.add(new Double(t.nextToken()));


              double a0 =  ((Double)x.get(0)).doubleValue();
               double b0 =  ((Double)y.get(0)).doubleValue();
                 double b1 =  ((Double)y.get(1)).doubleValue();
            if(b0 > b1) {

                 peaksx.add(new Double(a0));
                    peaksy.add(new Double(b0));

            for(int j=1; j<x.size()-1; j++){
                double a = ((Double)x.get(j)).doubleValue();
                             double b = ((Double)y.get(j)).doubleValue();
                         double bm1 = ((Double)y.get(j-1)).doubleValue();
                         double bp1 = ((Double)y.get(j+1)).doubleValue();
                if(b > bm1 && b > bp1){
                    peaksx.add(new Double(a));
                    peaksy.add(new Double(b));


               double ae =  ((Double)x.get(x.size()-1)).doubleValue();
               double be =  ((Double)y.get(x.size()-1)).doubleValue();
                 double be1 =  ((Double)y.get(x.size()-2)).doubleValue();
            if(be > be1) {

                 peaksx.add(new Double(ae));
                    peaksy.add(new Double(be));

        } catch(Exception ex){
              System.out.println("error " + ex.toString());



    public static void main(String [] args){
        new SineData();


Open in new window

This is the result:

[45000.0, 65000.0, 85000.0, 105000.0, 125000.0, 145000.0, 160000.0]

[10.0, 10.01, 10.005, 9.99987612345675, 10.02, 10.0, 4.99999999999999]

Open in new window


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