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Convert long to byte array to string representation

Hi all,

I'm working with a 3rd party com method with returns a "dword" which is 32 bits. The first 16 bits contains info, and the rest is empty.

Using c#, I'm trying to get the returned value (which I think is a long?), convert that value to a byte array, and then get the string representation of the whole lot.

What I'm hoping to end up with is something like this:
"0000 1011 0000 0000" - without the spaces.
Each bit represents an error message and this is why I need to shift through the string values at specific indexes etc.

Can someone please help with this, I'm getting nowhere fast.

Thank you in advance,

Sunny

Gene_Cyp

UInt32 can be converted using BitConverter.GetBytes

See: http://msdn.microsoft.com/en-us/library/1184xdy4.aspx

// Example of the BitConverter.GetBytes( uint ) method.
using System;

class GetBytesUInt32Demo
{
const string formatter = "{0,16}{1,20}";

// Convert a uint argument to a byte array and display it.
public static void GetBytesUInt32( uint argument )
{
byte[ ] byteArray = BitConverter.GetBytes( argument );
Console.WriteLine( formatter, argument,
BitConverter.ToString( byteArray ) );
}

public static void Main( )
{
Console.WriteLine(
"This example of the BitConverter.GetBytes( uint ) " +
"\nmethod generates the following output.\n" );
Console.WriteLine( formatter, "uint", "byte array" );
Console.WriteLine( formatter, "----", "----------" );

// Convert uint values and display the results.
GetBytesUInt32( 15 );
GetBytesUInt32( 1023 );
GetBytesUInt32( 0x100000 );
GetBytesUInt32( 1000000000 );
GetBytesUInt32( uint.MinValue );
GetBytesUInt32( int.MaxValue );
GetBytesUInt32( uint.MaxValue );
}
}

/*
This example of the BitConverter.GetBytes( uint )
method generates the following output.

uint byte array
---- ----------
15 0F-00-00-00
1023 FF-03-00-00
1048576 00-00-10-00
1000000000 00-CA-9A-3B
0 00-00-00-00
2147483647 FF-FF-FF-7F
4294967295 FF-FF-FF-FF
*/

Gene_Cyp

You can get your 0s and 1s by converting the HEX value into a binary value.

Hex - Binary
0 = 0000
1 = 0001
2 = 0010
3 = 0011
4 = 0100
.
.
.

ASKER CERTIFIED SOLUTION

Daniel Van Der Werken

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Mathiyazhagan

Could you post the dword value that you are getting from 3rd party com method? so that any one of us help you with possible solution.

Sunny_Kumar

ASKER

Thanks for all the help guys! Much appreciated!

sarabande

c# has the same bit operations as c and c++.

so you could do

if ((ui & (1<<i) != 0)

Open in new window

what would test whether the unsigned integer ui has bit value 1 at bit position i.

that works cause 1<<i moves bit 0 to bit i and the ui & operation makes a bitwise 'and' such that the result either is 0 (all bits are 0) or has exactly 1 bit at position i.

Sara

sarabande

there is a typo. it should be

if ((ui & (1<<i)) != 0)

Open in new window

Sara