<div>
Not really. Whatever is doing the finding will have to loop. Of course, you can try to avoid doing it yourself, even if something else has to. What exactly is it that you need to get?
</div>


Not really. Whatever is doing the finding will have to loop. Of course, you can try to avoid doing it yourself, even if something else has to. What exactly is it that you need to get?

<div>
if you know that this is &nbsp;this is the last occurrence you can use<br />
lastIndexOf()<br />
<br />

</div>


if you know that this is  this is the last occurrence you can use
lastIndexOf()



<div>
Matcher.find will find the beginning of the match if you give it the right pattern
</div>


Matcher.find will find the beginning of the match if you give it the right pattern

<div>
sVariable.matches(&quot;.*/.*/.<wbr />*/.*&quot;);
</div>


<div>
And of course if you want the remainder of the String<br />

<pre><code id="code-8140863">s = s.replaceAll(&quot;.*?/.*?/.*?(/.*)&quot;, &quot;$1&quot;); // (with the slash)

or

s = s.replaceAll(&quot;.*?/.*?/.*?/(.*)&quot;, &quot;$1&quot;); // (without the slash)</code></pre>
</div>


And of course if you want the remainder of the String


s = s.replaceAll(".*?/.*?/.*?(/.*)", "$1"); // (with the slash)

or

s = s.replaceAll(".*?/.*?/.*?/(.*)", "$1"); // (without the slash)

<div>
Sorry overlooked at your question..<br />
<br />
String s = &quot;a/bc/cd/f&quot;;<br />
System.out.println(s.repla<wbr />ceAll(&quot;.*/<wbr />.*/.*/(.*)<wbr />&quot;, &quot;$1&quot;));<br />
<br />
will print &quot;f&quot;
</div>


Sorry overlooked at your question..

String s = "a/bc/cd/f";
System.out.println(s.replaceAll(".*/.*/.*/(.*)", "$1"));

will print "f"

<div>
A simple loop will be the fastest, something like this:<br />
<br />
int matches = 0;<br />
int index = -1;<br />
for (int i=0; i&lt;s.length() &amp;&amp;&nbsp;matches&lt;3; i++) {<br />
&nbsp; &nbsp;if (s.charAt(i)=='/') matches++;<br />
&nbsp; &nbsp;if (matches==3) index = i;<br />
}<br />

</div>


A simple loop will be the fastest, something like this:

int matches = 0;
int index = -1;
for (int i=0; i<s.length() && matches<3; i++) {
   if (s.charAt(i)=='/') matches++;
   if (matches==3) index = i;
}


<div>
<div class="content wysiwyg-content">
Is there a faster way to find the third occurrence of a character within a string, rather than looping?<br />
<br />
PWo = sVariable.substring(0,(sVa<wbr />r2.indexOf<wbr />(&quot;/&quot;)+1))<br />
will give me the first occurrence.
</div>
</div>


Is there a faster way to find the third occurrence of a character within a string, rather than looping?

PWo = sVariable.substring(0,(sVar2.indexOf("/")+1))
will give me the first occurrence.

Java multiple occurrences within a string

Java is a platform-independent, object-oriented programming language and run-time environment, designed to have as few implementation dependencies as possible such that developers can write one set of code across all platforms using libraries. Most devices will not run Java natively, and require a run-time component to be installed in order to execute a Java program.

Java

JavaServer Pages (JSP) allow the development of dynamically generated web pages. It uses the Java programming language; JSP pages are translated into servlets at runtime, with each servlet being cached and reused until the JSP is modified. JSP allows Java code to be interleaved with static web markup content, so the resulting page can be compiled and executed on the server to deliver the content.