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GridView: Programmatically adding columns to the control (HyperLink)

Hi,

Minor problem here. I am trying to find a way to add programmatically columns to a GridView control. Most of the code I have read on the internet is unclear here.

Suppose I have a datatable filled with the following ids:
23424323
45645646
13123212

And I need to render a hyperlink as part of the gridview, where there is a column of hyperlinks like "edit.aspx?id=23424323", preferably with just the word "edit" showing.

Thanks,
Ryan

Imran Javed Zia

Hi,
Please use following
Thansk

<asp:GridView ID="grd" runat="server">
        <Columns>
            <asp:TemplateField>
                <ItemTemplate>
                    <asp:HyperLink ID="hpl" runat="server" Text="Edit" NavigateUrl='edit.aspx?id=<%# Eval("DBField") %>'></asp:HyperLink>
                </ItemTemplate>
            </asp:TemplateField>
        </Columns>
    </asp:GridView>

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rossryan

ASKER

Programmatically.

Imran Javed Zia

sorry there is typo use it as

<asp:HyperLink ID="hpl" runat="server" Text="Edit" NavigateUrl='<%# "edit.aspx?id=" + Eval("DBField") %>'></asp:HyperLink>

rossryan

ASKER

Hmm. Perhaps I should explain it like this:

I am looking for any code that let's me dynamically create those columns. What I mean is, I'm slotting this into a web control, and I do not know beforehand just how many columns will be hyperlink columns. The number of columns will be determined by the value I receive when the control is created.

Thanks,
Ryan

SOLUTION

Imran Javed Zia

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ASKER CERTIFIED SOLUTION

Carlos Villegas

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Carlos Villegas

I want to show you that you can add columns to your GridView in a easy way. This must be done before call GridView.DataBind() method.

HyperLinkField linkColumn = new HyperLinkField();
linkColumn.HeaderText = "Column Title";
GridView1.Columns.Add(linkColumn);

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