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You are getting 55 as that is the character code (see an ascii table) for the character you are supplying to the Double constructor. Although char represents a character, it is also a type of number, or bit pattern. In this case the char you supply is '7' but it's numeric value is actually 55.<br />
<br />
Since Double doesnt accept a char in its constuctor, it implicitly casts the char to double, in doing so working with the numeric value (55).
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You are getting 55 as that is the character code (see an ascii table) for the character you are supplying to the Double constructor. Although char represents a character, it is also a type of number, or bit pattern. In this case the char you supply is '7' but it's numeric value is actually 55.

Since Double doesnt accept a char in its constuctor, it implicitly casts the char to double, in doing so working with the numeric value (55).

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I'm attempting to push a character into:<br />
&nbsp;<br />
<b>Stack&lt;Double&gt; s = new Stack();</b><br />
<br />
By using the following line:<br />
<br />
<b>s.push(new Double(postfix.charAt(i)))<wbr />;</b><br />
<br />
However, when I push the character '7' for example and try to pop it using:<br />
<br />
<b>double a = ((Double) s.pop()).doubleValue();</b><br />
<br />
I get the decimal's character value 55 rather than the number 7. What am I doing wrong? What code will fix this?<br />

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I'm attempting to push a character into:
 
Stack<Double> s = new Stack();

By using the following line:

s.push(new Double(postfix.charAt(i)));

However, when I push the character '7' for example and try to pop it using:

double a = ((Double) s.pop()).doubleValue();

I get the decimal's character value 55 rather than the number 7. What am I doing wrong? What code will fix this?


Why is this character being pushed into the stack as it's decimal value?

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