asked on

How to insert thousands of records in sql table ?

i have the following table with following columns.
how to insert transid 200001 to 900004
in a single inert command, other columns values are same.

Companyid TransId Date
1 200001 21-Mar-2011
1 200002 21-Mar-2011
1 200003 21-Mar-2011
1 200004 21-Mar-2011
upto
1 900004 21-Mar-2011

Guy Hengel [angelIII / a3]

please try this:

;with cte as (
  select top 10 row_number() over (order by name) -1 rn from sys.objects 
)
, x as (
  select u1.rn + 10* u2.rn + 100*u3.rn + 1000* u4.rn + 10000*u5.rn + 100000*u6.rn  transid
    from cte u1
       , cte u2
       , cte u3
       , cte u4
       , cte u5
       , cte u6
  where u6.rn between 2 and 9
)
insert into yourtable
select 1 companyid, x.transid, convert(datetime, '2011-03-21', 120) [date]
  from x
 where transid >= 200001 
   and transid <= 900004
 order by transid

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kaminda

You can use a while loop

DECLARE @i INT
DECLARE @rows_to_insert INT 
SET @i = 200001    
SET @rows_to_insert = 900005   

WHILE @i < @rows_to_insert    
BEGIN     
INSERT INTO TABLE (Companyid,TransId,Date)
SELECT 1,@i,'2011-03-21'
SET @i = @i + 1 
END

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Alpesh Patel

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Asim Nazir

User Bulk insert command. Details: http://msdn.microsoft.com/en-us/library/ms188365.aspx

Gugro

Why would you do that ?
> how to insert transid 200001 to 900004
> in a single inert command, other columns values are same.
I would write a UDF ( User defined function ) which returns me for every TransID between 200001 to 900004 the company ID 1 and the date 21-Mar-2011