Algebra
How is this correct? I understand how they got 3/8 but not -y/8x. I get -y/0. Thanks.
y/8x+1/8-y/4x+1/4 = 3/8-y/8x
y/8x+1/8-y/4x+1/4 = 3/8-y/8x
abbright
y/8x-y/4x=1/8*(y/x)-1/4(y/
No way you can get anything over zero.
y/8x + 1/8 - y/4x + 1/4
(1/8 + 1/4) + (y/8x - y/4x)
(1/8 + 1/4) + y/x(1/8 - 1/4)ASKER
y/8x-y/4x = -0/4x
8-4=4
or a common denominator of 8x
y/8x y/8x
- y/4x 2y/8x
--------------
-y/0
8-4=4
or a common denominator of 8x
y/8x y/8x
- y/4x 2y/8x
--------------
-y/0
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ASKER
Are you saying that I only subtract the numerators and not the denominators?
ASKER
Thanks. I reviewed my previous book on subtracting fractions. I was trying to subtract the denominator.
What do you do with the numerators and the denominators in
1/8+1/4
?
1/8+1/4
?
>> Are you saying that I only subtract the numerators and not the denominators?
Definitely.
5/8 - 3/8 ==> Five eighths minus three is two eighths.
Just like five apples minus three apples is two apples.
5 apples minus 3 apples is not 2.
Definitely.
5/8 - 3/8 ==> Five eighths minus three is two eighths.
Just like five apples minus three apples is two apples.
5 apples minus 3 apples is not 2.
ASKER
I had forgotten that addition and subtraction are the same with regards to the denominators.
ASKER
5 apples minus 3 apples is not 2.
That's an effective analogy. Thanks.
That's an effective analogy. Thanks.