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Algebra

kadin
kadin asked
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Last Modified: 2012-05-11
How is this correct? I understand how they got 3/8 but not -y/8x. I get -y/0. Thanks.

y/8x+1/8-y/4x+1/4 = 3/8-y/8x
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Commented:
y/8x-y/4x=1/8*(y/x)-1/4(y/x)=(1/8-1/4)*(y/x)=(1/8-2/8)*(y/x)=-1/8*(y/x)=-y/8x
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Commented:
No way you can get  anything over zero.
y/8x + 1/8 - y/4x + 1/4     

     (1/8 + 1/4) + (y/8x - y/4x)   

     (1/8 + 1/4) + y/x(1/8 - 1/4)

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Commented:
y/8x-y/4x = -0/4x

8-4=4

or a common denominator of 8x

   y/8x  y/8x
 - y/4x  2y/8x
   --------------
           -y/0
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Commented:
Are you saying that I only subtract the numerators and not the denominators?

Author

Commented:
Thanks. I reviewed my previous book on subtracting fractions. I was trying to subtract the denominator.
ozo
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Commented:
What do you do with the numerators and  the denominators in
1/8+1/4
?
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Commented:
>>  Are you saying that I only subtract the numerators and not the denominators?

Definitely.

5/8 - 3/8  ==>  Five eighths minus three is two eighths.

Just like five apples minus three apples is two apples.


5 apples minus 3 apples is not  2.




Author

Commented:
I had forgotten that addition and subtraction are the same with regards to the denominators.

Author

Commented:
5 apples minus 3 apples is not  2.

That's an effective analogy. Thanks.
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