SQL max aggregate function

Posted on 2011-04-28
Medium Priority
Last Modified: 2012-05-11
I am trying to get the maximum from a result set so I can avoid receiving duplicates rows.  The field in question is totalgifts from the gifts_VIEW_donor_relations_simple table.  The field already contains the total for all gifts given, but it's duplicated for each fund (ie. if someone has given a total of $1000 but split it evenly between the building fund and the athletic fund, there would be two lines in the table with $1000 in each line in the totalgifts column).  The query I have setup is below:

use vcu

select c.coreid as ConstituentCoreID
      ,c.millid_married as MarriedID
      ,n1.namesmashd as BoardNameSort
      ,n1.nameformn as BoardName
      ,n.namesmashd as ConstituentSort
      ,n.nameformn as Constituent
      ,r.relstrtdat as StartDate
      ,r.relstopdat as StopDate
      ,r.rellook1 as Position
      ,r.relisa as Relationship
      ,cn.table_val ConstituentCode
      ,f.table_val as FoundationType
      ,d.deathdate as ConstituentDeathDate
      ,d1.deathdate as DisbandedDate
      ,g.totalgifts as TotalGifts
      ,i.intaddress as EMail
from corebio_VIEW_married_surviving c
      left outer join relation_full r on c.coreid=r.relid
      left outer join corebio_full c1 on r.relrelatid=c1.coreid
      join foundation_types f on c1.corefntype=f.table_code
      left outer join names_VIEW_preferred n on c.coreid=n.nameid
      left outer join names_VIEW_preferred n1 on c1.coreid=n1.nameid
      left outer join death_full d on c.coreid=d.deathid
      left outer join death_full d1 on c1.coreid=d1.deathid
      join constituent_types cn on c.coreconst=cn.table_code
      join gifts_VIEW_donor_relations_simple g on c.coreid=g.coreid      left outer join internetaddress_VIEW_preferred_email_NOT_INVALID i on c.coreid=i.intid
where f.table_type='board'
order by ConstituentSort
Question by:lcallah93
  • 2
LVL 40

Accepted Solution

mrjoltcola earned 2000 total points
ID: 35486224
Use MAX(g.totalgifts) and GROUP BY the rest of the fields.

Author Closing Comment

ID: 35486472
OMG - that was so EASY!!  Thank you, thank you, thank you!!!
LVL 40

Expert Comment

ID: 35486559
You are welcome. Glad to help. :)

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