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template and class questionc

Is there any way to write this statement without causing a compiling error? (illegal use of this type as an expression)

(line 15) {cout<<"Enter "<<n<<"data of "<<T<<" type: ";

Thanks.

#include<iostream>

using namespace std;

template<class T, int n>
class Two
{private: T a[n];
public: void Read();//read data into array a
		void Display();//display array a

};

template<class T, int n>
void Two<T ,  n>::Read()
{cout<<"Enter "<<n<<"data of "<<T<<" type: ";
for(int i= 0; i<n;++i)
	{cin>>a[i];}
}

template<class T, int n>
void Two<T,n>::Display()
{for(int i=0;i<n;++i)
{cout<<a[i]<<endl;}
}

int main()
{
Two<int,5> p;
p.Read();
p.Display();

return 0;}

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ASKER CERTIFIED SOLUTION

evilrix

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UltraDog

You'll have to overload the stream operators.
http://www.java2s.com/Code/Cpp/Overload/Overloadstreamoperator.htm

evilrix

How would overloading the stream operators help?

UltraDog

oops. Sorry, I was looking at the wrong line.
I thought that he wanted to print the value or receive input into an instance of type T using the "<<" or ">>" operator. :)

evilrix

Home now. The code below builds and does what I believe you are trying to do. My suggestion above does, indeed, work as I expected.

http://www.cppreference.com/wiki/language/typeid
http://www.cppreference.com/wiki/utility/rtti/type_info/start

#include<iostream>
#include <typeinfo>
using namespace std;

template<class T, int n>
class Two
{
private: T a[n];
public: void Read();//read data into array a
        void Display();//display array a

};

template<class T, int n>
void Two<T ,  n>::Read()
{
   cout<<"Enter "<<n<<" data of "<<typeid(T).name()<<" type: "; //< --- use typeid
   for(int i= 0; i<n;++i)
   {
      cin>>a[i];
   }
}

template<class T, int n>
void Two<T,n>::Display()
{
   for(int i=0;i<n;++i)
   {
      cout<<a[i]<<endl;
   }
}

int main()
{
   Two<int,5> p;
   p.Read();
   p.Display();

   return 0;
}

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