Square root

would it help if I said that y^(1/2) = sqrt(y)

I wish that statement helped me.

I just don't understand how that second to last equation became the last equation.

y^3/2 is 1 and 1/2

>> y^3/2 is 1 and 1/2

I'm not sure what you mean by that.

How about you write y^(3/2) as (y^3)^(1/2) and work from there ? ie. :

        (y^3)^(1/2) = x^7

I am out of time tonight. I will have to continue this tomorrow.

Thank you both for your help.

>> Thank you both for your help.

I'm glad I could help. Although it's strange that none of my posts were selected as (part of) the answer ;)