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Function passed to function

Hi All,

Can someone explain to me how the attached code works?
I understand the 3 and 4 are passed as the x and y parameters and the function is passed as the z parameter.. But i don understand what parameters are being passed to: function(x,y) { return x * y}??
Also, what is happening in the following line:
alert(z(x,y));

Thanks

function funcObject(x,y,z) {
   alert(z(x,y));
}

function testFunction() {

// third parameter is function
funcObject(3,4,function(x,y) { return x * y})
}

testFunction();

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Roman Gherman

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SOLUTION

dsmile

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oggiemc

ASKER

Thanks for reply guys..Unfortunately i still dont see where the actual multiplication of x * y is happening??

roma
\\ "alert(z(x,y));" - will call the function passed in parameter z with the two parameters: x and y.

so what you are saying is that above line is equivalent to:
alert(function(x,y) { return x * y}(x,y)); // i.e z = function(x,y) { return x * y}?

it all looks a bit confusing to me, and im not really sure what is the point of this technique?? Perhaps someone can enlighten me / explain in a bit more detail?

SOLUTION

Roman Gherman

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oggiemc

ASKER

alert(z(x,y));

So all the above line means is:

The z function i.e function(x,y) { return x * y} is called, and the x,y parameters are passed in to it?? I understand it is called an anonymous function, however i do not understand why such functions are used? What is the advantage over declarative functions?

thanks

SOLUTION

Roman Gherman

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