mssql database control with php

Posted on 2011-05-13
Medium Priority
Last Modified: 2012-05-11
I'm making a PHP script for controlling my mssql databases. But I ran into a couple of problems.

The first problem is that I want to make a combobox out of all the databases in my microsoft SQL server. With following code, but it doesn't seem to work.
SELECT name from sys.databases where owner_sid != 0x01

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My next problem is, that I have to run follwing SQL command:
RESTORE FILELISTONLY FROM DISK = 'C:\Databases\Breda\backup\Backup.BAK'

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But I need to get the first column of every row, and place that in 2 variables, but I don't know how to do that.

Can anyone provide me this code?
Question by:Silencer001
  • 3

Expert Comment

ID: 35753446
To answer your first problem, I believe you have to do this:

"SELECT name from master.sysdatabases where owner_sid != 0x01 "

I am not understanding your second question completly

Author Comment

ID: 35753593
And how do I put that code in a Combobox?

My second question is that if I execute that SQL statement, the following result comes up
 Output sql commandAnd I need to put the 2 LogicalNames into a variable.

So that row 1 column 1 (Breda) = $name1
and row 2 column 3 (Breda_log) = $name2

Because I need to use those 2 variables in the following code.

Accepted Solution

Silencer001 earned 0 total points
ID: 35775234
Found the solution, for the first problem it was:
$query = mssql_query("SELECT name FROM sys.databases");

		// Check if there were any records
				if (!mssql_num_rows($query)) {
					echo 'No records found';
					} else {
					echo "<select name='dbname'>";
						for ($i = 0; $i < mssql_num_rows($query); ++$i) {
						$lookup = mssql_result($query, $i, 'name');
							if ($lookup != "master" && $lookup != "tempdb" && $lookup != "model" && $lookup != "msdb" && $lookup != "SBO-COMMON" && $lookup != "RSP")
								echo "<option value='".$lookup."'>".$lookup."</option>";
					echo "</select>";

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and for the second problem it was:
$query = mssql_query("restore filelistonly from disk = '".$locatie."'");
	$lognaam1 = mssql_result($query, '0', 'LogicalName');
	$lognaam2 = mssql_result($query, '1', 'LogicalName');

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Author Closing Comment

ID: 35807144
Code works for 100%

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