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Query Issue

Robert Granlund
on
290 Views
Last Modified: 2012-06-27
I what the php to print this form and have the selections be in a specific order.  However, the following php prints the options in a random order.  The "Other" option, always seems to be printed as the second or third choice instead of the last choice.  Any ideas?

<?php
	$q = "SELECT exp_weblog_data.entry_id, exp_weblog_titles.entry_id, exp_weblog_data.field_id_308, exp_weblog_titles.entry_date, exp_weblog_data.field_id_195 FROM exp_weblog_data, exp_weblog_titles WHERE (exp_weblog_data.field_id_308 IS NOT NULL and length(exp_weblog_data.field_id_308) >= 3) AND exp_weblog_data.entry_id=exp_weblog_titles.entry_id AND exp_weblog_data.field_id_195='ARCHIVE' GROUP BY exp_weblog_data.field_id_308 ORDER BY
CASE
WHEN exp_weblog_data.field_id_308='red' THEN 1
WHEN exp_weblog_data.field_id_308='white' THEN 2
WHEN exp_weblog_data.field_id_308='bluer' THEN 3
WHEN exp_weblog_data.field_id_308='other' THEN 4 END";
	$r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc));
	if (mysqli_num_rows($r)) {  //  MAIN IF  //
?>

<form method="GET" action="MY ACTION/">
<h5>SEARCH BY COLOR</h5> <select name="guitar" style="width:100px;border:solid 1px #717171;background-color:#343333;color:#717171;">
<?php
		while ($row=mysqli_fetch_assoc($r)) { //  WHILE  
			$guitar = $row['field_id_308'];


				if($guitar=="red") { 
					echo "<option name=\"guitar\" value=\"red\">red</option>";
				}
		
				if($guitar=="white") { 
					echo "<option name=\"guitar\" value=\"white\">white</option>";
				}
		
				if($guitar=="blue") { 
					echo "<option name=\"guitar\" value=\"blue\">blue</option>";
				}
		
		
				if($guitar=="Other") { 
				echo "<option name=\"guitar\" value=\"Other\">Other</option>";
				}

			}  //  END WHILE
		}
?>
</select>
<br />
<input type="submit" name="submit" value="go" />
</form>

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