troubleshooting Question

MS Access Public Function returns error "Undefined function in expression

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Dumb_BlondeFlag for United States of America asked on
Microsoft Access
12 Comments1 Solution464 ViewsLast Modified:
Fair warning: I'm not a developer or an engineer. I'm a slightly-more-technical-than-most Business Analyst. My cheif qualifications for the project I'm working on are a subscription to Experts Exchange and being stubborn enough to keep searching until I find a solution here that solves the problem. So please use little words in any explanation. :)

I'm trying to split a long text field using multiple delimiters. I found the perfect solution here on EE posted by Alain Bryden (see below). I copied the code into a module in my DB.  The problem I'm having is that when I try to use the function in a query I get the error message "Undefined function in expression". I see the function listed in the expression builder. I have another function (also cribed from here) that works just fine when I select it in the expression builder. I've checked that there are no missing references and changed the module name (originally named the same as the function) to "Utilities". I'm at a loss here and rapidly running up against a deadline. Any help or suggestions you can offer would be much appreciated.

Function SplitMultiDelims(ByRef Text As String, ByRef DelimChars As String, _
        Optional ByVal IgnoreConsecutiveDelimiters As Boolean = False, _
        Optional ByVal Limit As Long = -1) As String()
    Dim ElemStart As Long, N As Long, M As Long, Elements As Long
    Dim lDelims As Long, lText As Long
    Dim Arr() As String
    lText = Len(Text)
    lDelims = Len(DelimChars)
    If lDelims = 0 Or lText = 0 Or Limit = 1 Then
        ReDim Arr(0 To 0)
        Arr(0) = Text
        SplitMultiDelims = Arr
        Exit Function
    End If
    ReDim Arr(0 To IIf(Limit = -1, lText - 1, Limit))
    Elements = 0: ElemStart = 1
    For N = 1 To lText
        If InStr(DelimChars, Mid(Text, N, 1)) Then
            Arr(Elements) = Mid(Text, ElemStart, N - ElemStart)
            If IgnoreConsecutiveDelimiters Then
                If Len(Arr(Elements)) > 0 Then Elements = Elements + 1
                Elements = Elements + 1
            End If
            ElemStart = N + 1
            If Elements + 1 = Limit Then Exit For
        End If
    Next N
    'Get the last token terminated by the end of the string into the array
    If ElemStart <= lText Then Arr(Elements) = Mid(Text, ElemStart)
    'Since the end of string counts as the terminating delimiter, if the last character
    'was also a delimiter, we treat the two as consecutive, and so ignore the last elemnent
    If IgnoreConsecutiveDelimiters Then If Len(Arr(Elements)) = 0 Then Elements = Elements - 1
    ReDim Preserve Arr(0 To Elements) 'Chop off unused array elements
    SplitMultiDelims = Arr
End Function

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