Pagination in xslt

you can try to insert some page generating instructions every 5 items, using the following sample:

<xsl:if test="position() mod 5 = 0">
--- new page ---
</xsl:if>

Thanks for your reply.

I am not that strong in xslt. Can you please help me in fixing my xslt  that how previous, next pagination will work

Thanks again

<xsl:choose>
	<xsl:when test="$type = 'open' ">

		<xsl:for-each select="//SUMMARY[CATEGORY/@CATEGORYID = $categoryID or $categoryID = 0][SUBCATEGORYID = $subCategoryID or $subCategoryID = 0][//SUMMARY/FORMATTEDDATE >= $today]">
			<xsl:sort select="//SUMMARY/FORMATTEDDATE " />
			SOME STUFF
		</xsl:for-each>		

	</xsl:when>

</xsl:choose>

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I can only give you general ideas.
Let's say we have an XML as follows:
<root>
<item>1</item>
<item>2</item>
.
.
</root>

The XSLT template could accept parameters, let's call them the "page" - for the page number (starting from 0) and the "num" - the number items on a page. A template like on the sample below will accept that params and output only the items for the specific page.
You need the "previous" and "next" commands (buttons?) to calculate the page number and pass the value to the template.

<xsl:template match="/root">
	<xsl:param name="page" select="0"/>
	<xsl:param name="num" select="6"/>
		
		<xsl:for-each select="item[position() &gt; $page * $num and position() &lt;= $page * $num + $num]">
			<xsl:value-of select="."/>,
  		</xsl:for-each>

</xsl:template>

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Thanks for your reply.

Here is the xml and xslt as you advised. Please help me in fixing xslt code snippet

For this test, say I need 2 records per page.

Please advice

Thanks again

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

	<!--end of xsl declarations-->
	<!-- global variables -->
	<!--<xsl:param name="tenderUniqueId" />-->

	<xsl:template match="/">
		<xsl:param name="page" select="0"/>
		<xsl:param name="num" select="2"/>

		<xsl:for-each select="//SUMMARY[position() &gt; $page * $num and position() &lt;= $page * $num + $num]">
			<xsl:value-of select="CATEGORY"/>
			<BR></BR>
		</xsl:for-each>

	</xsl:template>

</xsl:stylesheet>


<root>

	<SUMMARYNODE>
		<SUMMARY>
			<CATEGORY CATEGORYID="2">OPERATIONS PROCUREMENT</CATEGORY>
			<SUBCATEGORYID>4</SUBCATEGORYID>
		</SUMMARY>

	</SUMMARYNODE>


	<SUMMARYNODE>
		<SUMMARY>
			<CATEGORY CATEGORYID="2">XYZ</CATEGORY>
			<SUBCATEGORYID>6</SUBCATEGORYID>
		</SUMMARY>

	</SUMMARYNODE>

	<SUMMARYNODE>
		<SUMMARY>
			<CATEGORY CATEGORYID="5">ABC</CATEGORY>
			<SUBCATEGORYID>8</SUBCATEGORYID>
		</SUMMARY>

	</SUMMARYNODE>

	<SUMMARYNODE>
		<SUMMARY>
			<CATEGORY CATEGORYID="5">DHGFHGF</CATEGORY>
			<SUBCATEGORYID>8</SUBCATEGORYID>
		</SUMMARY>

	</SUMMARYNODE>

	<SUMMARYNODE>
		<SUMMARY>
			<CATEGORY CATEGORYID="5">JGHJLUJL H</CATEGORY>
			<SUBCATEGORYID>8</SUBCATEGORYID>
		</SUMMARY>

	</SUMMARYNODE>

</root>

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I changed the code a little to be compatible with the XML you provided.

To make the pagination work you need find a way to pass the current page number to the XSLT. It can be either stored in the XML or passed to the XSLT processor.

<xsl:param name="page" select="0"/>
<xsl:param name="num" select="2"/>

<xsl:template match="/">
	<xsl:for-each select="//SUMMARY">
		<xsl:if test="position() &gt; $page * $num and position() &lt;= $page * $num + $num">
			<xsl:value-of select="CATEGORY"/>
			<BR></BR>
  		</xsl:if>
	</xsl:for-each>
</xsl:template>

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Many Thanks for providing xslt which works good when we give page no.

Now here how do we count no of pages and run loop till to print no of pages.

This will help me in doing pagination completly

Thanks again

To calculate the number of the pages, you can use the following expression:
select="ceiling( count( //SUMMARY ) div $num)"

Please explain more specific, what you mean by "pagination" and how you think it should work.

Sorry, I was bit away from my work. I am back again. Please see attached the sample image that how I require the pagination
Please help

 

Many Thanks for your help. I will come back to you on this

Kind Regards

Many Many Thanks for your great help

you're welcome