asked on # Multiplication accurary

Hi,

working on a simple problem and wanted to get some ideas of the best way around it. Essentially I want to solve the following problem:

$0.75 * 120%

The answer is $0.90.

I have tried the following:

With the following output:

0.90000000000000000832667268468867405317723751068115234375

0.8999999999999999

0.8999999999999999

0.8999999999999999

0.9

0.9

working on a simple problem and wanted to get some ideas of the best way around it. Essentially I want to solve the following problem:

$0.75 * 120%

The answer is $0.90.

I have tried the following:

```
BigDecimal bd1 = new BigDecimal(.75);
BigDecimal bd2 = new BigDecimal(.2);
BigDecimal bd3 = new BigDecimal(1);
System.out.println( bd1.multiply(bd2.add(bd3)));
System.out.println( 0.75 * ( 1 + 0.20) );
System.out.println( .75d * 1.2d );
System.out.println( .75d / 5d * 6d);
System.out.println( 75d * 1.2d /100d);
System.out.println( .75d * (( 1d + 0.2d) * 100d)/100d );
```

With the following output:

0.900000000000000008326672

0.8999999999999999

0.8999999999999999

0.8999999999999999

0.9

0.9

Java

I think it should be like that for your code:

BigDecimal bd4 = bd1.multiply(bd2.add(bd3));

bd4 = bd4.setScale(2,RoundingMode.HALF_UP);

System.out.println("bd4: " + bd4);

Let me test.

BigDecimal bd4 = bd1.multiply(bd2.add(bd3))

bd4 = bd4.setScale(2,RoundingMod

System.out.println("bd4: " + bd4);

Let me test.

Yes, this worked for me:

```
BigDecimal bd1 = new BigDecimal(.75);
BigDecimal bd2 = new BigDecimal(.2);
BigDecimal bd3 = new BigDecimal(1);
BigDecimal bd4 = bd1.multiply(bd2.add(bd3));
bd4 = bd4.setScale(2,RoundingMode.HALF_UP);
System.out.println("bd4: " + bd4);
```

Output:

```
bd4: 0.90
```

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The answer is given to two parts as the explanation that a decimal can not be accurately represented via binary and that the constructors for BidDecimal should be with more accuracy. Thanks Everyone.

Look at this recent question with solution:

https://www.experts-exchange.com/Programming/Languages/Java/Q_27240925.html?sfQueryTermInfo=1+10+30+bigdecim+yan

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