asked on

change div content fade

i'm looking for a way to have a three or four buttons that control the content of a div with a jquery fade-in effect. I can't seem to find anything exactly like that through google. Just lots of image replacement code.

Can anyone help me find a way to have the content of a div change to/from various images and text when a button is clicked?

Thanks for your help!

leakim971

http://jqueryui.com/demos/tabs/

hibbsusan

ASKER

I found this code, but am having trouble making it swap content onclick

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>


</head>

<body>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script> 
 
<div id="tabs"><ul style="list-style:none">
     <li style="float:left;width:70px"> First</li>
	 <li style="float:left;width:70px"> Second </li>
	 <li style="float:left;width:70px"> Third </li>
	 <li style="float:left;width:70px"> Fourth </li>
	 <li style="float:left;width:70px"> Fifth </li>
   </ul>
   <ul style="clear:both">
   <div style="position:absolute"> first content</div>
   <div style="position:absolute"> second content</div>
   <div style="position:absolute"> third content</div>
   <div style="position:absolute"> fourth content</div>
   <div style="position:absolute"> fifth content</div>
   </ul></div>
 
 <script type="text/javascript">
 $('#tabs div').css({display:"none"});
 var li=document.getElementById('tabs').firstChild.getElementsByTagName('li');
 var div=document.getElementById('tabs').lastChild.getElementsByTagName('div');
 var actual;
 for (var i=0;i<li.length;i++)
 $(li[i]).bind("click",function(i)
 {	return function()
	{
    $(div[i]).fadeIn(1000);
	}
 }(i));
 for (var i=0;i<li.length;i++)
 $(li[i]).bind("mouseout",function(i)
 {return function()
	{
    $(div[i]).fadeOut(1000);
	}
 }(i));
 
 
 </script>
</body>
</html>

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has anybody got any suggestion?
Thanks!

hibbsusan

ASKER

That is to say, I changed the mouseover on line 35 to a click, but it still fades out when i mouseout.

here is a functional copy: http://jsfiddle.net/Q8Ybw/

Thanks

ASKER CERTIFIED SOLUTION

Pieter Marais

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