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UIIMageView ID ?

Posted on 2011-09-02
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Last Modified: 2012-05-12
Hello EE,

I was wondering if it was possible in XCode to put a tag or an ID to an UI Image view? My main concern is that once a user has touch the image I would to do something. But how can I know that he touches picture No. 3? or 2... or 6?

If it was possible to have an ID or tag or something so I can place the pictureID that comes from my database I could do anything I want...

any idea?
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Question by:PhilippeRenaud
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7 Comments
 
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Expert Comment

by:darbid73
ID: 36476947
All views in iOS have a tag property.

See here for the tag property..
Apple Reference for UIView

When I need to do what you want to do I either set the tag property in Interface builder or when creating the view with

imageView.tag = 101;

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Then somewhere at the top I have this

#define pic1 101

Now when I want to check what has been touched I use a test like this...

imageView.tag = pic1

Open in new window

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Author Comment

by:PhilippeRenaud
ID: 36478049
ok thanks.

but what if the ID or the value is a String?  tag i think is only integeR?
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Expert Comment

by:darbid73
ID: 36478491
the id cannot be a string, thus the reason why I define it as a string to make more sense.
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Author Comment

by:PhilippeRenaud
ID: 36478724
Alright for the Tag.

But one last thing, do you have an example on how you retrieve the tag on when you touch the image?

even if the tag is set, im confused on how I get the info on when the user touches the image he wants..
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Accepted Solution

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darbid73 earned 2000 total points
ID: 36478771
That really would be better done in a new question..... but here.  If you have problems open a new question and let me know.

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
	
	UITouch *touch = [touches anyObject];
    //you can see the view or its tag that was touched.
    NSLog(@"Touch View %@", [touch view]);

	
}

Open in new window

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Author Comment

by:PhilippeRenaud
ID: 36480426
Yes sorry should had done a new question.
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Author Closing Comment

by:PhilippeRenaud
ID: 36480427
thanks
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