Solved

Oracle query

Posted on 2011-09-06
5
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Last Modified: 2012-08-13
I've this table: TAB_USERS with column USER (name last + first name)

USER
Smith John
Smith David
Smith Jack
Di Martino Giovanni
De Nicola Antonio

I'd like to write a query with only upper (first name).

I tried this query:

select UPPER(substr (USER, instr(USER, ' ')+1))
from TAB_USERS;

But I've some problem with the names: Di Martino Giovanni and De Nicola Antonio

How can I write my query also considering the names with two spaces?

I'd like to get this output:

USER
JOHN
DAVID
JACK
GIOVANNI
ANTONIO
0
Comment
Question by:ralph_rea
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5 Comments
 
LVL 74

Expert Comment

by:sdstuber
ID: 36488823
select UPPER(regexp_substr(USER, '[^ ]+$')) from TAB_USERS;

0
 
LVL 74

Expert Comment

by:sdstuber
ID: 36488830
select UPPER(substr (USER, instr(USER, ' ',-1)+1))
from TAB_USERS;

0
 

Author Comment

by:ralph_rea
ID: 36488855
Ok, thanks bu now I've another problem, there are some users with this name: Smith John (USA)

How Can I avoid this problem??
0
 
LVL 74

Expert Comment

by:sdstuber
ID: 36488896
>> now I've another problem


select UPPER(regexp_substr(replace(USER,'(USA)'), '[^ ]$')) from TAB_USERS;


if you need something more sophisticated than that...

please open a new question,  list all the special parsing rules you want and how to identify them
0
 
LVL 74

Accepted Solution

by:
sdstuber earned 500 total points
ID: 36489409
sorry,  I missed some characters above...

 UPPER(regexp_substr(replace(usr,' (USA)'), '[^ ]+$'))

or, using the instr method...

UPPER(SUBSTR(REPLACE(usr, ' (USA)'), INSTR(REPLACE(usr, ' (USA)'), ' ', -1) + 1))
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