How can I set the equivlent of the "selectedIndex" of a DataGridViewComboboxCell?

bmsdev
bmsdev used Ask the Experts™
on
Basically, I want to set a "SelectedIndex" value of the comboboxcell.

From the code shown, objTypes object will contain something like:-
Value          Desc
10               First
20               Second
30               Third
etc....

I want to default some of the rows to specific values.  If I set the ".Value" property of the cell to 20, I want this to display "Second" within the combobox cell but I get the error attached as screen shot:-

Any help would be appreciated
 Error screen shot
Dim dgCombo As DataGridViewComboBoxCell = grdHeader.Rows(i).Cells("colType")
dgCombo.DataSource = objTypes
dgCombo.DisplayMember = "Desc"
dgCombo.ValueMember = "Value"

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Software Architect in .Net
Commented:
Dim dgCombo As DataGridViewComboBoxCell = grdHeader.Rows(i).Cells("colType")
dgCombo.DisplayMember = "Desc" 'With this you say that the combo must show the "Desc" value of each object added
dgCombo.ValueMember = "Value" 'With this you say that the value member of each object is the "Value" property or field
dgCombo.DataSource = objTypes 'Set the data source

dgCombo.Value = 4 'For example, with this the object with the value 4 in the "Value" property or field will be selected

Hope that helps.
x77

Commented:
A ComboBoxCell contains a ComboBox only when the cell is in Edit Mode.

Dgv has only One ComboBox or Textbox ... intance for all Cells.
Then you can access to Cell Control only when the Cell is in Edit Mode.

To Get the Control, you can use the Event Dgv_EditingControlShowing.
   At this point you can use E.Control and cast it to use apropiate methods an properties.
   Dgv_EditModeChanged, notifies edit mode changes.

At Cell Level, you can Override InitializeEditingControl and DetachEditingControl.

You can get the EditingControl from Dgv an cast It, but it is valid when cell is editing mode.

   Dim Cmb = TryCast(Dgv.Editingcontrol,DataGridViewComboBoxEditingControl)
   if cmb isnot nothing ....

Author

Commented:
That worked perfictly.  I did origionally have that code, but the ".Value" property is a Decimal, and i was setting it to an Integer.  Thanks for you help.

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