How to trap FTP error
Dear Experts,
I have the following script. It set as a cron job. It works fine if the file is present on the server, but if it is not, the script hangs.
How can I trap the failure and then exit from the script?
I have the following script. It set as a cron job. It works fine if the file is present on the server, but if it is not, the script hangs.
How can I trap the failure and then exit from the script?
ASKER
Thank you, WalkaboutTigger, for your quick response.
When i open ftp process, can I do something like
echo `ls -l abc*` > abc.log
When i open ftp process, can I do something like
echo `ls -l abc*` > abc.log
ASKER
I made the following changes/additions in my initial script and solved the problem.
#! /bin/bash
v_rundir="/home/abc"
v_ftp=`cat ftp.log | grep "not found" | wc -l`
cd $v_rundir
rm ftp.log
# Test to see if this process is already running...
if [ -e process.lck ] ; then # if it is, then exit...
exit
fi
echo $$ > process.lck # otherwise, lock this process from duplicated execution...
#FTP Function
# Get the new pgp files...
sftp username@ftp4.server.com <<EOF >>/home/abc/ftp.log 2>&1
cd abc/Toabc
mget abc*.txt.pgp
rm abc*.txt.pgp
quit
EOF
if [ $v_ftp -ne "0" ]; then
rm process.lck
exit 1
fi
exitASKER CERTIFIED SOLUTION
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If no lines are returned, the file does not exist.