asked on

mysqli query Not returning rows but error of mysql_query() expects parameter 2 to be resource

I worked with this problem for about 3 hours. So-called soluiions do Not work and some are mixed mysqli and mysql. Below is some code that gives the error of "mysql_query() expects parameter 2 to be resource". I have no idea what resource they are talking about!

$conn1 = new mysqli($hostName1, $userName2, $password2, $databaseName1) ;
/* check connection */
      if (mysqli_connect_errno()) {
            printf("Connect failed: %s\n", mysqli_connect_error());
            exit(); // <==///========
      }
echo ' database ' . $databaseName1 . ' is now connected to program. ' ;

      // Create SQL code to insert a record into the Prospect table.
      $SQL1 = "INSERT INTO Prospect (CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile) ";
      $SQL1 .= " VALUES('N', 'Y', 'John', 'Hammer', 'John@HammondTrees.com', 'Test only in 2011' )";

$conn1->query($SQL1); // run the query
      printf (" | New Record has id %d.\n", $conn1->insert_id);
      echo ' \ Prospect table ' ;
// this works OK, but not the Select section below

      // use a Select to show current records
      $SQL1 = "SELECT CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile " ;
      $SQL1 = " FROM Prospect " ;
      // $result1 = $conn1->query($SQL1) ;
      // $result1 = mysql_query( $link1, $SQL1) ;
      // associative array
      // $row22 = mysqli_fetch_array($result1, MYSQLI_ASSOC);

     echo "CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile " ;

     // $last1 = mysql_query( $SQL1 , $link1) ;
      $last1 = mysql_query( $SQL1 ) ;
     $totalRows1 = mysql_num_rows($last1);
     while ( $addToArray1 = mysql_fetch_array($last1) )
     {
            // This could be placed in a table.
            echo " " . $row['CustomerYN'] . " " ;
            echo "<br />" ;
     }

jeff_01

I think the issue is here

$SQL1 = "SELECT CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile " ;
$SQL1 = " FROM Prospect " ;

TRY

$SQL1 = "SELECT CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile " ;
$SQL1 .= " FROM Prospect " ;

Dave Baldwin

You can't mix 'mysql' and 'mysqli' functions and expect thing to work right. This page http://us2.php.net/manual/en/mysqli.query.php shows two different ways to use 'mysqli' and this page http://us2.php.net/manual/en/function.mysql-query.php shows a similar thing for 'mysql' . If you try to mix the two different methods, your results will be unpredictable.

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Dave Baldwin

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jeff_01

Either way the query will not work with the "." missing as effectively the query would be just

mysql_query("FROM prospect");

instead of

mysql_query("SELECT CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile FROM prospect");

KennethSumerford1

ASKER

I had to add two ;'s and then it worked great! Thanks soooo much! The code was accurate, complete and easy for a beginner PHP programmer to understand. I have more than 10 years experience with VB but PHP has some weird coding, at times. I did take your code, make a few edits and create the function below.

function fnAddRecSeletRecs($hostName1, $userName3, $password3, $databaseName3 ) {
            // Add one record and display all records in the Prospect table.

      try {
            $conn1 = new mysqli($hostName1, $userName3, $password3, $databaseName3) ;
      /* check connection */
      if (mysqli_connect_errno()) {
            printf("Connect failed: %s\n", mysqli_connect_error());
            exit(); // <==///========
            }
      echo ' database ' . $databaseName3 . ' is now connected to program. ' ;

      // Create SQL code to insert a record into the Prospect table.
      $SQL1 = "INSERT INTO Prospect (CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile) ";
      $SQL1 .= " VALUES('N', 'Y', 'John', 'Hammer', 'John@HammondTrees.com', 'Test only in 2011' )";

      $conn1->query($SQL1); // run the query
      printf (" | New Record has id %d.\n", $conn1->insert_id);
      echo ' \ Prospect table ' ;
      // this works OK, but not the Select section below

      // use a Select to show current records
      $SQL2 = "SELECT CustomerYN, ActiveYN, FirstName, LastName, EmailMain, CoProfile " ;
      $SQL2 .= " FROM Prospect " ;
      $result2 = $conn1->query($SQL2) ;
      $K1 = 0 ;

      while($row22 = $result2->fetch_array(MYSQLI_ASSOC)) {
            $K1 = $K1 + 1 ;
      echo $K1 . " ";
      echo "CustomerYN = ".$row22["CustomerYN"].", ActiveYN = ".$row22["ActiveYN"].", ";
      echo "FirstName = ".$row22["FirstName"].", LastName = ".$row22["LastName"].", ";
      echo "EmailMain = ".$row22["EmailMain"].", CoProfile = ".$row22["CoProfile"]."<br>";
      } // == end of while

      /* close connection */
      $conn1->close();
      return true ; // <===///==========
} // === end of try

catch ( Exception $e1) {
      echo " error in database and table operations-- " . $e1 . " | " ;
            return false ; // <===///==========
}
} // === end of function ======================

--- Kenneth

Dave Baldwin

You're welcome. I didn't have a chance to test it since I didn't have a matching database so I'm not surprised I missed something.