asked on

Return middle part of a string

I have a string that looks like the following:

firstword_secondword_thirdword_TheWordIWant_fifthword_sixthword_seventhword.csv

I am looking for a vba function that would be most efficient to return the "TheWordIWant" string.

I am wanting this to look like the following:

Function GetTabName(strFileName as String, strDelimiter as String, intDelimiterOccurance as Integer) as String

End Function

Randy Downs

Try this

http://www.ozgrid.com/VBA/extract-words-function.htm

Extract nth Word From Text in Excel See
Also: Extracting Words From Text in Excel using Excel Built in Function/Formulas and Find Nth Occurrence

With the aid of Excel VBA we can write a custom formula/function, or user defined function to extract out the nth word from a text string. The code below should be placed in a standard Excel Module after entering the VBE. That is, push Alt+F11 and then go to Insert>Module and paste in the code below;

Option Compare Text

Function Get_Word(text_string As String, nth_word) As String

Dim lWordCount As Long

With Application.WorksheetFunction

lWordCount = Len(text_string) - Len(.Substitute(text_string, " ", "")) + 1

If IsNumeric(nth_word) Then

nth_word = nth_word - 1

Get_Word = Mid(Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
.Find("^", .Substitute(text_string, " ", "^", nth_word)), 256), 2, _
.Find(" ", Mid(Mid(.Substitute(text_string, " ", "^", nth_word), 1, 256), _
.Find("^", .Substitute(text_string, " ", "^", nth_word)), 256)) - 2)

ElseIf nth_word = "First" Then

Get_Word = Left(text_string, .Find(" ", text_string) - 1)

ElseIf nth_word = "Last" Then

Get_Word = Mid(.Substitute(text_string, " ", "^", Len(text_string) - _
Len(.Substitute(text_string, " ", ""))), .Find("^", .Substitute(text_string, " ", "^", _
Len(text_string) - Len(.Substitute(text_string, " ", "")))) + 1, 256)

End If

End With

End Function

ASKER CERTIFIED SOLUTION

nutsch

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Helen Feddema

You can use the Split function to do this (I did it in Access, but I think it would work in Excel VBA too):

Public Function ThirdName(strFullString As String) As String
   
   Dim strFullText() As String
   Dim intUBound As Integer
   
   'Extract third name from full name
   strFullText = Split(strFullString, "_", -1, vbTextCompare)
   intUBound = UBound(strFullText)
   ThirdName = strFullText(2)

End Function

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Helen Feddema

The intUBound line is redundant (I modified this from another function that used it)

nutsch

fixing error on line 6

Function gettabname(strFileName As String, strDelimiter As String, intDelimiterOccurance As Integer) As String
Dim arr As Variant

arr = Split(strFileName, strDelimiter)

gettabname = arr(intDelimiterOccurance - 1)

End Function

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ckelsoe

ASKER

I am accepting this solution over others as it is simple with the least amount of coding to achieve the intended result. This is not to say that other code presented would not work. I did note the correction in Line 6 and had made the same correction to meet my specific goals.

Thanks for the quick response.

nutsch

Glad to help. Thanks for the grade.

Thomas