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The method presented by pepr does round the result. &nbsp;If you truly want to truncate the result, I think you'd have to do something like:<br />
<br />
a = 17.5678<br />
<br />
length_of_final_string = len('%.*f' % (number_of_decimal_places,<wbr /> a))<br />
<br />
b = str(a)[:length_of_final_st<wbr />ring]
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Hi<br />
<br />
I have a decimal value which I have calculated. I want to convert this to a string but only to a certain precision e.g. 2 decimal places. Can anybody tell me how to do this?<br />
<br />
Issac
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Hi

I have a decimal value which I have calculated. I want to convert this to a string but only to a certain precision e.g. 2 decimal places. Can anybody tell me how to do this?

Issac

The method presented by pepr does round the result.  If you truly want to truncate the result, I think you&#39;d have to do something like:

a = 17.5678

length_of_final_string = len(&#39;%.*f&#39; % (number_of_decimal_places, a))

b = str(a)[:length_of_final_string]

decimal places in a string

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