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how to do multiple partitioning

Posted on 2011-09-08
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Last Modified: 2012-05-12
Hi everyone

I was wondering if its possible to partition a set of data then get this data and partition it again?

My scenarios are
1) Need to firstly check that a register which has the same date, time, staff_code, week_no, and course I want to only pick the modules beginning with m (b.aos_code sorted desc)
2) Having carried out the first check I then need check the data for registers that occur same date, time, staff_code, week_no which have two courses attached in this case I want to select the highest nvq_lvl and if the nvq_lvls are the same then check the hrs_total

I have seperated both scenarios into partitions but im not sure if you can do what I have attached below ie do you need to partition and then store in a table and then partition again?
(I have removed the tables to shorten the code)

Help appreciated
select acad_period, register_id, register_group, staff_code, week_no, day_of_week, date, [month_no],
start_time, end_time,
convert(varchar, convert(int,floor([Total Hours])))+':'+
replicate('0',(2 - len(convert (varchar, convert(int,([Total Hours] - floor([Total Hours])) * 60.0)))))
+convert (varchar, convert(int,([Total Hours] - floor([Total Hours])) * 60.0)) as 'Total Hours',
dept_code, 
[m_code], [m_period], [m_desc], [c_code], [c_period], [c_desc], 
[c_moa], [c_hrs], nvq_lvl_ind, [rn], [rn1]


FROM
(
			select a.acad_period, a.register_id, a.register_group, a.staff_code,
			a.week_no,
			c.day_of_week, g.date,
			left(CONVERT ( char(20) , g.date , 101 ),2) as 'month_no',
			c.start_time, c.end_time,
			ROUND(cast((datediff(mi, MIN(c.start_time), MAX(c.end_time))  / 60.0) as FLOAT),2) AS 'Total Hours',
			c.dept_code, 
			b.aos_code as 'm_code', b.aos_period as 'm_period', f.full_desc as 'm_desc',
			e.aos_code as 'c_code', e.aos_period as 'c_period', e.full_desc as 'c_desc', e.moa_code as 'c_moa',
			e.hrs_total as 'c_hrs',
			h.nvq_lvl_ind,
			row_number() over (partition by a.register_id, a.register_group, a.staff_code, a.week_no, c.day_of_week, g.date,
							c.start_time, c.end_time, e.aos_code, e.aos_period
                         order by b.aos_code desc ) as rn ,
			row_number() over (partition by a.register_id, a.register_group, a.staff_code, a.week_no, c.day_of_week, g.date,
							c.start_time, c.end_time
                         order by h.nvq_lvl_ind, e.hrs_total desc ) as rn1 

			from tables ....

			where a.acad_period = '10/11'

			group by a.acad_period, a.register_id, a.register_group, a.staff_code, a.week_no,
			c.day_of_week, g.date, c.start_time,
			c.end_time, c.dept_code, 
			b.aos_code, b.aos_period, f.full_desc,
			e.aos_code, e.aos_period, e.full_desc, 
			e.moa_code, e.hrs_total, h.nvq_lvl_ind

) X

where (rn = 1 and rn1 = 1)

order by staff_code, [c_code], [c_period], register_id, register_group, date

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Question by:lisa_mc
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6 Comments
 
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Expert Comment

by:lcohan
ID: 36505633
No you can't. SQL table Partitioning is based on a single partition key and that's why is so important to choose the right partitioning key before you do it.

"The partition key must exist as a single column in the table and must meet certain criteria."
http://msdn.microsoft.com/en-us/library/ms345146(v=sql.90).aspx#sql2k5parti_topic9


from general topic
http://msdn.microsoft.com/en-us/library/ms345146(v=sql.90).aspx
0
 
LVL 3

Author Comment

by:lisa_mc
ID: 36509138
Hi Icohan

I didnt think I could do that becasue everytime I executed it I was getting a different number of rows so I know something wasn't right.

Do you know is there any other way to do this ie could I partition then rank - sort of briefly looked it up last night so need to look at it more.

Or should I just do the first partition copying the results into a #temp_table then carry out the second partition

what do you think - do you have any suggestions?

Thanks
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Accepted Solution

by:
lisa_mc earned 0 total points
ID: 36510411
thinking about this more and more I have figured out that I only ever need one partition because I dont care what the class name is - is not important to me as long as I have the course description but by using the partition

row_number() over (partition by a.register_id, a.register_group, a.staff_code, a.week_no, c.day_of_week, g.date,
                                          c.start_time, c.end_time
                         order by h.nvq_lvl_ind, e.hrs_total desc ) as rn1

This will only ever pick one row therefore I do not need to carry out another partition before this

I was so deep into thinking about this I made it much more difficult than it should have been
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LVL 3

Author Closing Comment

by:lisa_mc
ID: 36534646
I have accepted my own comment as it turns out I only ever need one partition because even if I do select a register which doesn't have a module (beginning with m) attached (using partition rn) I will always gets the correct answer using (partition Rn1) because I don't care what the module name is I am only extracting the course details
0
 
LVL 39

Expert Comment

by:lcohan
ID: 36511646
My objection is that I gave an answer to the question AS IT WAS posted however all the comments above and further to that are not related and far from that.
0
 
LVL 3

Author Comment

by:lisa_mc
ID: 36521187
Hi Icohan

I also asked another question which was

>> I have seperated both scenarios into partitions but im not sure if you can do what I have attached below ie do you need to partition and then store in a table and then partition again? <<

But from your first comment you haven't answered this

I also thought that you maybe could have advised me as to why I was trying to partition twice when I only needed to ever partition once as one partition will only ever bring out one line of data.  Especially since in the second partition I mentioned nothing about modules therefore is not seen as important

I did not ask how to partition as I had attached code showing that I understood this - whereas your answer shows me how to structure a partition correctly and why use partitioning (which I did not ask)

I don't have a problem with assigning points but I am not going to give them away when I feel I came to answer the question first - sorry
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