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Hello, i been trying to write my own pow function but it's not working out.. when i enter "base 2, power 3" gives me 4... not sure what my problem is..

```
#include <iostream>
using namespace std;
int CalcPower(int base, int power)
{
int total;
for (int i =0; i<power; ++i)
{
total = base * base;
return total;
}
}
int main(void)
{
int one;
int two;
cout <<"please type in your base" <<endl;
cin >> one;
cout <<"please type in your power" <<endl;
cin >> two;
CalcPower(one,two);
cout<<endl;
cout << CalcPower(one,two);
}
```

```
int total = base;
```

can't i just write
```
int total; total = base * base
```

is that the same thing your doing here..? thanks
```
int total;
total = base;
```

instead of```
int total = base;
```

In the first snippet the variable total is first declared and then initialized.In the second snippet this is done a single step.

BUT: base is not the same as base * base!

I'll try to explain the code I gave you in my first post:

This checks if power is 0. If so the result is per definition 1, so we can just return that.

```
if(power == 0)
{
return 1;
}
```

The next step is to declare the variable we will use to calculate the result.Since we already handled the case that power is 0 with the code above we can assume that power is at least 1. As base^1 is just base we can use this value to initialize total.

```
int total = base;
```

Now for the loop. If power is 1 the variable total already holds the correct result, so we don't have to enter the loop. That's why i starts at 2. If power is 2 or higher it will enter the loop an multiply the product of previous iterations (held in total) by base.```
for (int i =2; i<=power; ++i)
{
total = total * base;
}
```

At the end we simply have to return the value stored in total and we're done.```
return total;
```

Just walk it through with power = 3:power is != 0, so we initialize total = base

no the loop: i = 2 which is <= 3

total becomes total * base which equals base * base

next step: i = 3 which is <= 3

total becomes total * base which equals base * base * base

next step: i = 4 which is > 3

the loop is exited and total is returned as the result

total is now base * base * base which is base^3.

I hope that cleared things up a bit,

Frank

```
#include <iostream>
using namespace std ;
/*
Compile time options on Linux:
g++ -Wall fileName.C
Remove the warning messages during compilation.
*/
/*
Add comments here for describing the function CalcPower and the parameters.
*/
int CalcPower( int base, int power)
{
/* int total ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
int total = 0 ;
for ( int i =0 ; i < power ; ++i)
{
/* total = base * base ; */
total += base * base ; /* Replace = with += */
/* return total ; This needs to be added at the end of this function */
}
/* warning: control reaches end of non-void function */
/* Hence write the following statement */
return total ; /* Always use return for each functions */
}
/*
Add comments here for describing the function main and the parameters.
*/
int main( void)
{
/* int one ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
/* int two ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
int one = 0 ;
int two = 0 ;
cout << "please type in your base" <<endl ;
cin >> one ;
cout << "please type in your power" <<endl ;
cin >> two ;
CalcPower( one, two) ;
"calPow.C" 50 lines, 1611 characters
bectest2@aix52 /develop/bectest2/.Murugesan/tcp [ 0 ]
$ mk
make: 1254-004 The error code from the last command is 2.
Stop.
xlC -g calPow.C
^[/bectest2@aix52 /develop/bectest2/.Murugesan/tcp [ 0 ]
$ cat calPow.C
#include <iostream>
using namespace std ;
/*
Compile time options on Linux:
g++ -Wall fileName.C
Remove the warning messages during compilation.
*/
/*
Add comments here for describing the function CalcPower and the parameters.
*/
int CalcPower( int base, int power)
{
/* int total ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
int total = 0 ;
for ( int i =0 ; i < power ; ++i)
{
/* total = base * base ; */
total += base * base ; /* Replace = with += */
/* return total ; This needs to be added at the end of this function */
}
/* warning: control reaches end of non-void function */
/* Hence write the following statement */
return total ; /* Always use return for each functions */
}
/*
Add comments here for describing the function main and the parameters.
*/
int main( void)
{
/* int one ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
/* int two ; Initialize all variables at the definition location. (To resolve the valgrind reported issues) */
int one = 0 ;
int two = 0 ;
cout << "please type in your base" <<endl ;
cin >> one ;
cout << "please type in your power" <<endl ;
cin >> two ;
CalcPower( one, two) ;
cout << endl ;
cout << CalcPower( one, two) ;
cout << endl ;
return 0 ; /* Always use return for each functions */
}
```

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you have your return statement inside the loop, so it returns just at he end of the first iteration.

Also you simply assign to total the value of base * base. Given that base is 2 this will always be 4 no matter how often you iterate through the loop.

You should also check wether power is 0 or 1. If it's 0 the return value is always 1 and if it's 1 then the return value is base istself.

Change your code to:

Open in new window

Hope that helps,

Frank