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MySQL: Query from within BASH script

This MySQL query is successfully executed from a MySQL command line:
INSERT INTO `Group_Members` (`GroupID`,`MemberID`) SELECT '22', `ID` from `Member` m WHERE `UserSuspended` != '1' AND `PremPlusMember` != '1' AND `PremWebMember` = '1' AND `SMSMember` != '1' AND NOT EXISTS( select null from Group_Members g WHERE g.GroupID = 22 and g.MemberID = m.ID )

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However when I try to put it in a BASH script like this, I get an error:
echo "INSERT INTO `Group_Members` (`GroupID`,`MemberID`) SELECT '22', `ID` from `Member` m WHERE `UserSuspended` != '1' AND `PremPlusMember` != '1' AND `PremWebMember` = '1' AND `SMSMember` != '1' AND NOT EXISTS( select null from Group_Members g WHERE g.GroupID = 22 and g.MemberID = m.ID )" | mysql -u xyz -pabc123 -h m.example.com -D xyz_db

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Group_Members: Command not found.
GroupID: Command not found.
MemberID: Command not found.
ID: Command not found.
Member: Command not found.
UserSuspended: Command not found.
PremPlusMember: Command not found.
PremWebMember: Command not found.
SMSMember: Command not found.
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax;
0
hankknight
Asked:
hankknight
2 Solutions
 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
you don't run it from "bash" itself, but using mysql command line tool:
http://dev.mysql.com/doc/refman/5.5/en/mysql.html
mysql db_name < script.sql > output.tab

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spock787Commented:
Assuming the command and SQL itself is correct, the backticks need to be excaped... try this...

echo "INSERT INTO \`Group_Members\` (\`GroupID\`,\`MemberID\`) SELECT '22', \`ID\` from \`Member\` m WHERE \`UserSuspended\` != '1' AND \`PremPlusMember\` != '1' AND \`PremWebMember\` = '1' AND \`SMSMember\` != '1' AND NOT EXISTS( select null from Group_Members g WHERE g.GroupID = 22 and g.MemberID = m.ID )" | mysql -u xyz -pabc123 -h m.example.com -D xyz_db

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