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C#. LINQ TO XML

Below is just a sample of my xml that I want to add too. What I want to do is be able to traverse through adding information to each parent foler.
In my example below folder name="national" has numberOfRecords 2 as it only has 2 as the total number of records inside that folder. Whereas folder
name outlet has a total number of records equal to seven as there are seven files under it. and so does folder name C, and so on. I want to be able
to traverse through and add a new attribute (numberOfRecords) to folders, national, outlet & C. I am trying to make this completely
generic so that whatever is added, can also be correctly calulated. I mean each folder can have as many folders as can be, each with as many files as can be.

I am using C#. LinqToXML, Basically I dont want to use the words folder and file at all, I want to do it all using LINQS alternative to XPATH AXES.

I know it sounds complex. Though I'm sure it is not to someone out there as it is a fairly common task to perform.

Thanks in advance.
<?xml version="1.0" encoding="utf-8"?>
<myData>
  <items id="0">
    <folder name="C">
      <folder  name="outlet">
        <folder name="national" >
          <folder name="dir2" numberOfRecords="0"/>
          <folder name="dir3" numberOfRecords="2">
            <file name="tester"  />
            <file name="helper" />
          </folder>
          <folder numberOfRecords="5" />
            <file name="help"  />
            <file name="tester2" />
            <file name="tester3" />
            <file name="tester4" />
            <file name="tester5" />
          </folder>
        </folder>
      </folder>
    </folder>
  </items>
</myData>

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metta0_3
Asked:
metta0_3
  • 3
1 Solution
 
disruptCommented:
This link will give you an example how you can get values, remove and update.
http://www.xmlplease.com/update-xml-linq
http://stackoverflow.com/questions/670563/linq-to-read-xml-c
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käµfm³d 👽Commented:
You should be able to do something like the following:

using System;
using System.Linq;
using System.Xml.Linq;

namespace Application
{
	class MainClass
	{
		public static void Main (string[] args)
		{
			XDocument xdoc = XDocument.Load("input.xml");
			
			foreach (var folder in xdoc.Descendants("folder"))
			{
				var numberOfRecords = folder.Attribute("numberOfRecords");
				
				if (numberOfRecords == null)
				{
					numberOfRecords = new XAttribute("numberOfRecords", string.Empty);
					folder.Add(numberOfRecords);
				}
				
				numberOfRecords.Value = folder.Descendants("file").Count().ToString();
			}
			
			xdoc.Save("output.xml");
		}
	}
}

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Now I know you said you didn't want to use the words "folder" or "file", but I'm not sure how you'd avoid using either since you have other nodes that occur in your document. If you plan on including a record count for the myData and items nodes, then the above code could be modified. I'm also not sure what your requirement for discriminating which nodes get a "numberOfRecords" attribute without evaluating the name. If you can elaborate, then the code above could be modified.
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metta0_3Author Commented:
Hi, thanks for your help. I was hoping to use XPATH axes. This is great what you have given me. Essentially folder is just an example. There is about 10 different things that can be in its place, all called different things. So I want it too just look at it as a node regardless of what it is called. Just to save code. Otherwise I have to write what you have provided for each node other than folder.

I do also want the item attribute to consist of numberOfRecords, because it is the top level element, so will store the totals. myData element is just a wrapper.

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metta0_3Author Commented:
Its ok though, its not a problem using the nodenames I was just hoping for an alternative, I will use it your way, using logical AND, will award you kaufman once it is doing as desired.
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metta0_3Author Commented:
Right, I used your way and it resolved the issue completely. I just called every node folder and then created an attribute called type. Then just used your code and it was brilliant.

Thanks for your help.
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