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Command Line PHP variable

Posted on 2011-09-11
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Last Modified: 2012-05-12
I am able to issue command line php such as:

C:\>php test.php

And everything runs fine.

But, when I try to send a variable:

C:\>php test.php?my_variable=hello

It fails with a:

Could not open input file test.php?my_variable=hello

Where am I going wrong?
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Question by:hrolsons
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5 Comments
 
LVL 82

Accepted Solution

by:
leakim971 earned 500 total points
ID: 36520721
>Where am I going wrong?

the system try to find the file test.php?my_variable=hello (and not file test.php as you want)
C:\>php test.php hello

Open in new window


in you code (test php) :
<?PHP

echo $_SERVER["argv"][1];

?>

Open in new window

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LVL 83

Expert Comment

by:Dave Baldwin
ID: 36520962
"test.php?my_variable=hello" is something a web server would recognize as a URL with a query string.  That is not the way it is done on the command line because the command line version does not run thru the web server.  I think you need to come to an understanding of the difference because you have several questions here that confuse those two different ways of running PHP.
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LVL 110

Expert Comment

by:Ray Paseur
ID: 36521703
Instead of running PHP from the command line, I always put my scripts on my web server and test them there, over the internet, in the live environment that is exactly where they will run, when they are released into the wild.  It saves me a lot of confusion.  You might want to think about that.  My "build process" usually consists of Save->Ftp->Refresh.  Lather, rinse, repeat.  Easy!
0
 

Author Comment

by:hrolsons
ID: 36523859
Ray,

I totally see what you're saying, but in this case, the php file is manipulating images(adding the border), and will never leave my machine.
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