# Help understanding IFF(

Experts,
I'm trying to understand a query I've inherited that encompasses IFF( as seen below:

IIf([check amount] Between 60 And 80,9,IIf([check amount] Between 80 And 100,12,IIf([check amount] Between 100 And 120,15,IIf([check amount] Between 120 And 140,18,IIf([check amount] Between 140 And 160,21,IIf([check amount] Between 160 And 180,27,IIf([check amount] Between 180 And 200,30,IIf([check amount]>200,30,0)))))))) AS [held fee]

Can somebody please explain in English what's going on here?
###### Who is Participating?

x

VBA ExpertCommented:
This is the basic logic with the input value ([check amount]) on the left and the output ([Held Fee]) on the right.

Check Amount     Held Fee
60-80                      9
80-100                    12
100-120                  15
120-140                  18
140-160                  21
160-180                  27
180-120                  30
>200                      30

Or is it the whole syntax of the Iif you want explained?
0

Commented:
Nested IIF statements can be confusing.  This is the same as:

If [check amount] Between 60 And 80 Then
Held Fee = 9
elseif [check amount] Between 80 And 100 then
Held Fee = 12
Elseif [check amount] Between 100 And 120 then
Held Fee = 15
Elseif [check amount] Between 120 And 140 then
Held Fee = 18
Elseif [check amount] Between 140 And 160 then
Held Fee = 21
Elseif [check amount] Between 160 And 180 Then
Held Fee = 27
Elseif [check amount] Between 180 And 200 Then
Held Fee = 30
Elseif [check amount]>200 then
Held Fee = 30
Else
Held Fee = 0
End If

Of course you cannot use BETWEEN like this in vba code, but you get the idea.  Personally, I prefer to use the Switch function.  In your query, it would look like:

SWITCH([check amount] < 60, 0, [check amount] < 80, 9, [check amount]< 100, 12, [check amount] < 120, 15, [check amount] < 140, 18, [check amount] < 160, 21, [check amount]<180, 27, [check amount] >= 180, 30, True, 0)

which is a little easier to read, and because the criteria are evaluated in order, you don't need to include the lower limit in the equation.
0

Commented:
the first IIF
IIf([check amount] Between 60 And 80,9
* is testing the value of [Check AMount] is in the range of 60 to 80 and to return a value of 9

* if the value is not satisfied by the first condition ( range of 60 to 80 ) it test the next
IIf([check amount] Between 80 And 100,12

and so on,

and if nothing in the IIF expression was satisfied , return a value of 0

*NOTE

you have an overlapping ranges of values

Between 60 And 80

Between 80 And 100

that should written like this

Between 60 And 79

Between 80 And 99

Between 100 And 119

and so on

0

Author Commented:
thanks - I noticed the overlapping values - these developers just did such a poor job
0

VBA ExpertCommented:
By the way, you could probably cut the expression down.

I tried a few things but the 'blip' from 21 to 27 throws it off.
0
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