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Excel 2008 - Find last cell with data in row

Posted on 2011-09-13
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Last Modified: 2012-05-12
I've searched for an answer, but it seems that I can only find VBA-based solutions, which appears to no longer be an option in Excel 2008.  

I'm trying to return the name of the last cell in a row that contains data.  

So, it looks like this:

+===========================================================+
                 A      /  B  /  C  /  D  /  E  (columns)
+===========================================================+
1         || [Formula] /  3  /  4  /  5  / [blank]
2         || [Formula] /  7  /  8  / [blank] / [blank]
3         || [Formula] /  9  / 10 / 11 / 12
(rows)
+===========================================================+

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 And, the end result would look like this:

+===========================================================+
               A       /  B  /  C  /  D  /  E  (columns)
+===========================================================+
1         || D1 /  3  /  4  /  5  / 
2         || C2 /  7  /  8  /     / 
3         || E3 /  9  / 10 / 11 / 12
(rows)
+===========================================================+

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Question by:n00b0101
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10 Comments
 
LVL 18

Expert Comment

by:krishnakrkc
ID: 36529711
Hi,

try

=index(b$1:e$1,match(9.99999e+307,b2:e2))

Kris
0
 
LVL 50

Expert Comment

by:barry houdini
ID: 36529737
Try this formula in A1 copied down

=ADDRESS(ROW(),MATCH(9.99E+307,1:1),4)

regards, barry
0
 
LVL 35

Expert Comment

by:Norie
ID: 36529739
Are you using a Mac?

There are formulas to get the last value in a row, for example

=LOOKUP(9.99E+99,2:2)

Put this in A1 in and be copy down.

I'm sure getting the address, eg D1, etc but that's a but beyond me.
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LVL 18

Expert Comment

by:krishnakrkc
ID: 36529758
Hi

Ignore the earlier post. Try

=CELL("address",INDEX(C1:K1,MATCH(9.9999E+307,B1:K1)))

Kris
0
 

Author Comment

by:n00b0101
ID: 36529948
I've tried all of these, but it returns #N/A.  In some cases, the cell will contain text... I tried altering the MATCH statement to:

MAX(MATCH(9.9999E+307,B8:RJ8),MATCH(REPT("z",255),B8:RJ8))

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But, it continues to return #N/A
0
 
LVL 18

Assisted Solution

by:krishnakrkc
krishnakrkc earned 800 total points
ID: 36530004
Hi,

=CELL("address",INDEX(C1:K1,MAX(IFERROR(MATCH(9.9999E+307,B1:K1),0),IFERROR(MATCH("zzzzzzzzz",B1:K1),0))))

Kris
0
 
LVL 50

Expert Comment

by:barry houdini
ID: 36530014
For text or numbers....

=ADDRESS(ROW(),MATCH(2,INDEX(1/(1:1<>""),0)),4)

regards, barry
0
 
LVL 50

Expert Comment

by:barry houdini
ID: 36530027
My version goes in A1, clearly for the range B8:RJ8 change to this in A8

=ADDRESS(ROW(),MATCH(2,INDEX(1/(B8:RJ8<>""),0)),4)

barry
0
 
LVL 50

Accepted Solution

by:
barry houdini earned 1200 total points
ID: 36530076
Sorry, scratch that last one, for that version to work the range should start at column A. Perhaps an amalgamation of the formula suggested by Kris....and my one, i.e. in A8

=CELL("address",INDEX(B8:IV8,MATCH(2,INDEX(1/(B8:IV8<>""),0))))

regards, barry
0
 

Author Closing Comment

by:n00b0101
ID: 36530243
Thanks, this one works.  I'm splitting the points (hopefully, fairly)...
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