Solved

how to sum in xslt

Posted on 2011-09-13
4
395 Views
Last Modified: 2013-11-18
i want use sum function.  Here i want perform the sum which in bold,
To help you i have given like this.
[ In this for loop i want sum each xsl:value-of ]

<xsl:template name="getContentiousAmount">
      <xsl:param name="partyReference" as="xs:string"/>
            <xsl:for-each select="../../../../../../facilityPosition/positionInfo/position[positionTypeCode/upper-case(code) = 'FACILITYENDOFPERIODCONTENTIOUSAMOUNT']">
             <xsl:chose>
                   <xsl:when test="../position[positionTypeCode/upper-case(code) eq 'FACILITYENDOFPERIODUNPAIDAMOUNT']">
                         <xsl:value-of select="0"/>                   </xsl:when>
                   <xsl:otherwise>
                         <xsl:value-of select="../../drawdownPosition/positionInfo/position
                  [positionTypeCode/upper-case(code) eq 'DRAWDOWNENDOFPERIODUNPAIDAMOUNT'][partyReference/@href eq $partyReference]
                  //positionAmounts/node()[name() eq  'positionAmount']/amount"/>
                  </xsl:otherwise>
             </xsl:chose>                  
            </xsl:for-each>
      </xsl:template>
CPMPROD-D-CPM-LOA-20110617-0000-.XML
0
Comment
Question by:nkk1712
  • 3
4 Comments
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 36529986
just wrap a sum around it
<xsl:value-of select="sum(../../drawdownPosition/positionInfo/position
                  [positionTypeCode/upper-case(code) eq 'DRAWDOWNENDOFPERIODUNPAIDAMOUNT'][partyReference/@href eq $partyReference]
                  //positionAmounts/node()[name() eq  'positionAmount']/amount)"/>  
0
 

Author Comment

by:nkk1712
ID: 36533936
please check its a for loop and i want to have sum for the both conditions
Example
the result of the above may give like this....

     0
     250
     350
     0
     500

now i want the sum as  [0 +  250 + 350 + 0 + 500] = 1100.
Acutally its and condition. i am not able to get the proper result when use xpath as
folllows

sum(../../../../../../../facilityPosition[positionInfo[position
                  [positionTypeCode/upper-case(code) eq 'FACILITYENDOFPERIODCONTENTIOUSAMOUNT'][partyReference/@href eq $partyReference]]
                  [position[positionTypeCode/upper-case(code) !='FACILITYENDOFPERIODUNPAIDAMOUNT']]]
                  /drawdownPosition/positionInfo/position[positionTypeCode/upper-case(code) eq 'DRAWDOWNENDOFPERIODUNPAIDAMOUNT']
                  [partyReference/@href eq $partyReference]//positionAmounts/node()[name() eq $elementName]/ag:getPositionAmount(amount, currency, $tag_Currency))
0
 
LVL 60

Accepted Solution

by:
Geert Bormans earned 500 total points
ID: 36534567
"sum(../../../../../../facilityPosition[positionInfo/position[positionTypeCode/upper-case(code) = 'FACILITYENDOFPERIODCONTENTIOUSAMOUNT']]/drawdownPosition/positionInfo/position
                  [positionTypeCode/upper-case(code) eq 'DRAWDOWNENDOFPERIODUNPAIDAMOUNT'][partyReference/@href eq $partyReference]
                  //positionAmounts/node()[name() eq  'positionAmount']/amount)"

will work (since the second condition returns zero, so you don't need to add them)

note that your XML has a namespace,
so facilityPosition does not exist, except in the namespace
since this seems to do something for you,
- you either have stripped out the namespace prior to your XSLT
- you are using default x-path namespace in XSLT2

if none of teh above is true, you need to add prefixes everywhere for that namespace

and...
usually there is little reason for not replacing ../../../../../../../facilityPosition
with ancestor::facilityPosition
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 36534568
the sum() by the way is outside the loop
0

Featured Post

Space-Age Communications Transitions to DevOps

ViaSat, a global provider of satellite and wireless communications, securely connects businesses, governments, and organizations to the Internet. Learn how ViaSat’s Network Solutions Engineer, drove the transition from a traditional network support to a DevOps-centric model.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This article covers the basics of the Sass, which is a CSS extension language. You will learn about variables, mixins, and nesting.
What is Node.js? Node.js is a server side scripting language much like PHP or ASP but is used to implement the complete package of HTTP webserver and application framework. The difference is that Node.js’s execution engine is asynchronous and event…
The viewer will learn how to count occurrences of each item in an array.
Video by: Mark
This lesson goes over how to construct ordered and unordered lists and how to create hyperlinks.

791 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question