Set notation vs SQL

Scenario: In my organisation I want to identify the PCs having only authorised software installed.

To do this I could compare the applications installed on each PC with my list of authorised applications.  Using set theory / notation the solution is easy to express i.e. a PC is considered authorised if its applications are a subset of the authorised list.
What I’m trying to get my head around is how this ‘solution’ could be implemented using SQL? I’m after some sound pointers or approaches.
Thanks.
antonmsAsked:
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Kevin CrossConnect With a Mentor Chief Technology OfficerCommented:
antonms,

The principal is the same. Another way to look at this under set theory / notation is that no member of the PC's set of applications is outside the set of authorised ones.

Therefore, in SQL you can use EXISTS and NOT EXISTS to your favor. Basically, you can query for the rows where there does not exist another row for the same PC that has an application not listed on the authorised list, i.e., an application that does not match to a row in your authorised applications table.

In general terms:

SELECT {column list}
FROM A a1
WHERE NOT EXISTS (
   SELECT 1
   FROM A a2
   LEFT OUTER JOIN B b1 ON a2.AppID = b1.AppID
   WHERE a2.PcID = a1.PcID AND b1.AppID IS NULL
)

You can do the second piece with a NOT EXISTS as well, but wanted to show OUTER JOIN is also an option. But with NOT exists, you can find the PCs that have an invalid app but finding that the app does not exist in the authorised apps table. Then to find PCs with only authorised apps, you check for the inverse of that list. So top level could also use NOT IN if you replace SELECT 1 with SELECT PcID and remove filter on PcID in the inner queries WHERE clause.

Hopefully that isn't too convoluted an explanation and everything makes sense.

Kevin
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JestersGrindCommented:
Instead of looking at the PCs that only have authorized software installed, you could exclude the PCs that do not have authorized software installed.  That would be an easier query to write.

Greg



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