Solved

tsql: How can I get this result set?

Posted on 2011-09-15
4
242 Views
Last Modified: 2012-05-12
TSQL:
From a table such as this

DateTime                  Value                  Node
01/01/2011 10:00:00            10                  N1
01/01/2011 10:00:00            100                  N2
01/01/2011 10:01:00            20                  N1
01/01/2011 10:01:00            200                  N2
01/01/2011 10:02:00            30                  N1
01/01/2011 10:02:00            300                  N2
01/01/2011 10:03:00            40                  N1
01/01/2011 10:03:00            400                  N2
01/01/2011 10:04:00            50                  N1
01/01/2011 10:04:00            500                  N2
01/01/2011 10:05:00            60                  N1
01/01/2011 10:05:00            600                  N2



How can a query create the following result. The where clause should be related to date and time and node

I can get the value from node 1 easily but I also need node2 in the same result set.

Node1                  Node2
10                  100
20                  200
30                  300
40                  400
50                  500
60                  600


Thanks
0
Comment
Question by:stevejknight
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
4 Comments
 
LVL 15

Expert Comment

by:tim_cs
ID: 36543462
What you're looking for is a pivot statement.

http://msdn.microsoft.com/en-us/library/ms177410.aspx
0
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 230 total points
ID: 36543467
select max(case when node = 'N1' then value end) node1
, max(case when node = 'N2' then value end) node2
from yourtable
group by DateTime                  
0
 
LVL 15

Expert Comment

by:tim_cs
ID: 36543496
Totally read that wrong the first time.  Thought you were adding the values.  

0
 
LVL 50

Assisted Solution

by:Lowfatspread
Lowfatspread earned 20 total points
ID: 36543796
like this

select a.[value] as node1,b.[value] as node2
from (select x.* 
            ,row_number() over (partition by [datetime] order by [value]) as rn
        from yourtable as x
        where node='n1') as a
full outer join 
     (select x.* 
            ,row_number() over (partition by [datetime] order by [value]) as rn
        from yourtable as x
        where node='n2') as b
on a.[datetime]=b.[datetime]
and a.rn=b.rn
order by coalesce(a.[datetime],b.[datetime]),coalesce(a.rn,b.rn)

Open in new window

0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Long way back, we had to take help from third party tools in order to encrypt and decrypt data.  Gradually Microsoft understood the need for this feature and started to implement it by building functionality into SQL Server. Finally, with SQL 2008, …
There have been several questions about Large Transaction Log Files in SQL Server 2008, and how to get rid of them when disk space has become critical. This article will explain how to disable full recovery and implement simple recovery that carries…
Finds all prime numbers in a range requested and places them in a public primes() array. I've demostrated a template size of 30 (2 * 3 * 5) but larger templates can be built such 210  (2 * 3 * 5 * 7) or 2310  (2 * 3 * 5 * 7 * 11). The larger templa…
Finding and deleting duplicate (picture) files can be a time consuming task. My wife and I, our three kids and their families all share one dilemma: Managing our pictures. Between desktops, laptops, phones, tablets, and cameras; over the last decade…

738 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question