Solved

Random 0 showing up after form filled out

Posted on 2011-09-15
1
258 Views
Last Modified: 2012-05-12
On this page, http://bit.ly/pXD3H8, if you just hit submit and not fill anything in you'll see my error messages.

Any thoughts on why the "0" is showing up at the end of this line.

Please use the"BACK" button to try again.0

Code below.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Payday</title>
</head>
<style type="text/css">
body  {background-color:#9c9; margin:100px; font-size:36px; text-align:center; text-decoration:underline}
</style>

<body>

<?php
	
	
	function display($fieldName){
		echo "The field \"$fieldName\" is required.<br/>";
	}
	function validateWage($data, $fieldName){
		global $errorCount;
		if(empty($data)){
			display($fieldName);
			++$errorCount;
			$retval = "";
		}else{
			$retval = trim($data);
			$retval = stripslashes($retval);
			if (is_numeric($data)){
				$retval = round($data, 2);
			}else{
				echo "<p> Incorrect entry. You must enter a number.</p>";
				++$errorCount;
				$retval = "";
			}
			return($retval);
		}
	}
	$errorCount = 0;
	
	$wage =  validateWage($_POST['wage'], "Hourly wage");
	$hours = validateWage($_POST['hours'], "Hours worked");
	if ($errorCount>0){
		echo "Please use the\"BACK\" button to try again.";
	}else{
		 	echo "You Got PAID: $";
	}
	if ($hours>40){
		$OTHours = $hours - 40;
		$OT = $wage * .5;
		$pay = $wage * $hours;
		echo $OT * $OTHours + $pay;
	}else{
	$pay = $wage * $hours;
	echo $pay;
	}

?>
</body>
</html>

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Comment
1 Comment
 
LVL 34

Accepted Solution

by:
Beverley Portlock earned 500 total points
ID: 36546412
It looks to me like you have a misplaced { }. Instead of

     if ($errorCount>0){
          echo "Please use the\"BACK\" button to try again.";
     }else{
               echo "You Got PAID: $";
     }
     if ($hours>40){
          $OTHours = $hours - 40;
          $OT = $wage * .5;
          $pay = $wage * $hours;
          echo $OT * $OTHours + $pay;
     }else{
     $pay = $wage * $hours;
     echo $pay;
     }

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it would make more sense to be like this

     if ($errorCount>0){
          echo "Please use the\"BACK\" button to try again.";
     }else{
               echo "You Got PAID: $";
               if ($hours>40){
                         $OTHours = $hours - 40;
                         $OT = $wage * .5;
                         $pay = $wage * $hours;
                         echo $OT * $OTHours + $pay;
               }else{
                    $pay = $wage * $hours;
                    echo $pay;
               }
     }

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0

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