Solved

# Producing Monthly Totals with SQL

Posted on 2011-09-15
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I've never tried this with SQL, but I'm sure it's possible.
I have data prepared nicely with the following self-explanatory fields:

ID, DAILY_AMOUNT, TERM_START, TERM_END

I want to turn this into a report that yields total DAILY_AMOUNT where the selection criteria specify a start and end date.
So, for example, this could be used to answer the question, "How much did I spend on widgets in July of 2010?".
So If I spent \$5 every day on widgets from, say, 2010/6/12 to 2010/7/5, the answer would be \$25 (\$5 x 5 Days in July).

What's the smart way to do this?

Mike
0
Question by:shacho
• 5
• 3
• 2
• +1

LVL 25

Expert Comment

select year(TERM_END),month(TERM_END), sum(DAILY_AMOUNT)
from tabelname
where TERM_END between   .. and ..
group by year(TERM_END),month(TERM_END)
0

Author Comment

That would work if I had individual records for each day.  I don't I only have the "daily amount".  So I need to calculate how many days the expense term and the extraction term have in common.  If I have that number, I can multiply by the daily amount to get the sum.
0

LVL 4

Expert Comment

Hi

Please find the TSQL statement below:

DECLARE @TERM_STARTDATE datetime
DECLARE @TERM_ENDDATE datetime

SET @TERM_STARTDATE  = '05/05/2010' (Input: Start date of the period)
SET @TERM_ENDDATE ='05/08/2010' (Input: End date of the period)

SELECT sum(ISNULL(DAILY_AMOUNT,0) * DATEDIFF(day,TERM_START, TERM_END)) as amount FROM table_name WHERE DATEDIFF(day,@TERM_STARTDATE, TERM_START) >=0  AND DATEDIFF(day,@TERM_ENDDATE, TERM_END) <=0
0

Author Comment

I can't quite see how that would work.  There are several scenarios that need to be considered, e.g. ranges that don't overlap, partially overlap, are sub or super sets of each other, etc.  This is how I do it (in Access with VBA) right now.  This may clarify what the actual data look like.  This is a fine solution, but SQL would be much faster.

Public Function OverLap(TermStart As Date, TermEnd As Date, RangeStart As Date, RangeEnd As Date) As Integer
Dim StartDate As Date, EndDate As Date
OverLap = 0
If TermEnd < RangeStart Then Exit Function
If TermStart > RangeEnd Then Exit Function
If RangeEnd < TermEnd Then EndDate = RangeEnd Else EndDate = TermEnd
If RangeStart > TermStart Then StartDate = RangeStart Else StartDate = TermStart
OverLap = EndDate - StartDate + 1
End Function
0

LVL 4

Expert Comment

hi

I believe the above conditions are satisfied by sql query pasted below. Can you test the sql query for a date range?

DECLARE @TERM_STARTDATE datetime
DECLARE @TERM_ENDDATE datetime

SET @TERM_STARTDATE  = '05/05/2010' (Input: Start date of the period)
SET @TERM_ENDDATE ='05/08/2010' (Input: End date of the period)

SELECT sum(ISNULL(DAILY_AMOUNT,0) * DATEDIFF(day,TERM_START, TERM_END)) as amount FROM table_name WHERE DATEDIFF(day,@TERM_STARTDATE, TERM_START) >=0  AND DATEDIFF(day,@TERM_ENDDATE, TERM_END) <=0
0

LVL 22

Accepted Solution

Thomasian earned 500 total points

``````SELECT SUM(DAILY_AMOUNT
* DATEDIFF(day, CASE WHEN TERM_START>@RangeStart
THEN TERM_START
ELSE @RangeStart
END
, CASE WHEN TERM_END>@RangeEnd
THEN TERM_END
ELSE @RangeEnd
END
)
) As [Amount]
FROM tablename
WHERE ID=@ID
AND TERM_START<=@RangeEnd
AND TERM_END>=@RangeStart
``````
0

Author Comment

There we go.  Essentially an SQL version of my VB function.  Nifty.
0

LVL 25

Expert Comment

In calculation that must be datediff + 1
with case you can select the apropriate date
``````DECLARE @TERM_STARTDATE datetime
DECLARE @TERM_ENDDATE datetime

SET @TERM_STARTDATE  = '05/05/2010' -- (Input: Start date of the period)
SET @TERM_ENDDATE ='05/08/2010' --(Input: End date of the period)

select year(TERM_END) as y,month(TERM_END) as m
, sum(ISNULL(DAILY_AMOUNT,0)
* (DATEDIFF(day,
(case when TERM_START > @TERM_STARTDATE then TERM_START else @TERM_STARTDATE end)
, (case when TERM_END < @TERM_ENDDATE then TERM_END else @TERM_ENDDATE end))
+1) as amount
from tablename
where TERM_END >= @TERM_STARTDATE
and TERM_START <= @TERM_ENDDATE
group by year(TERM_END),month(TERM_END)
``````
0

Author Comment

indeed
0

LVL 25

Expert Comment

sorry for duplicate, aswer was waiting for submit when I got a long call :)
0

Author Comment

np - thanks for commenting.
0

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