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What is wrong with this MySQL statement?

Posted on 2011-09-17
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Last Modified: 2012-05-12
The statement below does not give an error code, but it does not compute the TIMEDIFF:

"UPDATE Stop_times, Start_times
SET Stop_times.Project_Charge_Time=TIMEDIFF(Stop_times.STOPid,Start_times.STARTid)
WHERE Start_times.PROJECTid = Stop_times.PROJECTid
AND
Start_times.EMPLOYid=Stop_times.EMPLOYid"

but if you delete the update and modify it to a select statement like '/**UPDATE Stop_times, Start_times
SET Stop_times.Project_Charge_Time=/**/  SELECT TIMEDIFF(Stop_times.STOPid,Start_times.STARTid)
FROM Stop_times, Start_times
WHERE Start_times.PROJECTid = Stop_times.PROJECTid
AND
Start_times.EMPLOYid=Stop_times.EMPLOYid

it computes the time difference correctly
0
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Question by:ToreJohn
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7 Comments
 
LVL 60

Expert Comment

by:Kevin Cross
ID: 36554322
Hi. You said it does not throw an error; therefore, how are you judging that it did not compute?
0
 
LVL 60

Expert Comment

by:Kevin Cross
ID: 36554337
The syntax you have looks fine, so suspect something else. For example, by naming convention, I would not expect the actual time values to be in a column STARTid or STOPid. When I see that I think AUTO_INCREMENT or INT fields that are keys to a table. Try the below syntax ensuring that the columns in TIMEDIFF are indeed DATETIME columns. Since you said this works in SELECT, that may be the STARTid and STOPid, but may be worth double checking.

UPDATE Stop_times stp
JOIN Start_times strt 
    ON strt.PROJECTid = stp.PROJECTid
   AND strt.EMPLOYid = stp.EMPLOYid
SET stp.Project_Charge_Time = TIMEDIFF(stp.STOPdatetime, strt.STARTdatetime)
;

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0
 

Author Comment

by:ToreJohn
ID: 36554366
I can see that it does not work because stp.Project_Charge_Time is 0000-00-00 00:00:00 also after running the query. Your alternative code gives the same result. (When I modified stp.STOPdatetime to STOPid and the same for STARTid)
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LVL 60

Expert Comment

by:Kevin Cross
ID: 36554372
Wait. Project_Charge_Time is a datetime?
Remember TIMEDIFF is given you a difference in time values. It is not resulting in a datetime value. Please show the table structure(s) and some sample data with what you expect the final results to be.
0
 

Author Comment

by:ToreJohn
ID: 36554431
Yes and Thanks.
I used datetime as the format for the output. Changing the format did the trick
0
 
LVL 60

Accepted Solution

by:
Kevin Cross earned 2000 total points
ID: 36554441
You are welcome!
0
 

Author Closing Comment

by:ToreJohn
ID: 36554450
It was fine. He understood that what I had done was correct and pointed me in the right direction.
0

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