Vector Calculus: Finding the vector equation of the line tangent to r(t) at point P
Posted on 2011-09-19
Find a vector equation of the line tangent to the graph of r(t) at the point P on the curve:
r(t) = (2t-1)i + sqrt(3t+4)j ; P(-1,2)
The answer I got was:
r'(t) / || r'(t) || =
sqrt(4 + ( 9 / (12t + 16) )
Not sure if the above is right. First time my professor said it was wrong, then claimed it was right, but when asked a third time to see if it really was, never got a clear answer so I'm confused.