• Status: Solved
• Priority: Medium
• Security: Public
• Views: 408

# Vector Calculus: Finding the vector equation of the line tangent to r(t) at point P

Find a vector equation of the line tangent to the graph of r(t) at the point P on the curve:

r(t) = (2t-1)i + sqrt(3t+4)j ; P(-1,2)

T(t) =
r'(t) / || r'(t) || =

<2, 3/2(3t+4)^(-1/2)>
/
sqrt(4 + ( 9 / (12t + 16) )

Not sure if the above is right. First time my professor said it was wrong, then claimed it was right, but when asked a third time to see if it really was, never got a clear answer so I'm confused.
0
Zenoture
1 Solution

Commented:

>>Not sure if the above is right

It looks like you have calculated the unit vector

0

Author Commented:
Yes, I calculated the unit tangent vector instead of the vector tangent to the line, i.e. r'(t), doh! Over thinking things is bad haha.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.