Short sed script

I need a sed script that will look for an occurrence of aaaaa followed two lines later by an occurrence of bbbbbb.
xoxomosAsked:
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woolmilkporcConnect With a Mentor Commented:
How about this?

This time it's not a one-liner (and it's not sed but grep).
I tried to make it a bit more detailed as usual.

The script will not only tell you verbatim what it found (or not found) but will also set different return codes.
So if you want to rely on these codes instead of the messages just redirect the script's stdout to /dev/null (or to a logfile, if desired).

Adjust the variables according to your needs.

wmp
#!/bin/bash
FILE=/path/to/inputfile
STRING1="aaaaa"
STRING2="bbbbb"
DISTANCE=2
L1=$(grep -n "$STRING1" $FILE |cut -f1 -d":")
if [[ ! -z $L1 ]] ; then
 L2=$(grep -n "$STRING2" $FILE |cut -f1 -d":")
   if [[ ! -z $L2 ]] ; then
     if [[ $(($L2 - $L1)) -eq $DISTANCE ]] ; then
       echo "SUCCESS! $STRING1 found at line $L1, $STRING2 found at line $L2"
       RC=0
       else echo "$STRING1 ($L1) and $STRING2 ($L2) found, but distance is not $DISTANCE lines!"
            RC=1
     fi
     else echo "$STRING1 found, but $STRING2 not found!"
     RC=2
   fi
   else echo "$STRING1 not found!"
   RC=3
fi
exit $RC

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xoxomosAuthor Commented:
Thanks.  I'll give it a try.
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