Short sed script

Posted on 2011-09-20
Medium Priority
Last Modified: 2012-05-12
I need a sed script that will look for an occurrence of aaaaa followed two lines later by an occurrence of bbbbbb.
Question by:xoxomos
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LVL 68

Accepted Solution

woolmilkporc earned 1000 total points
ID: 36572422
How about this?

This time it's not a one-liner (and it's not sed but grep).
I tried to make it a bit more detailed as usual.

The script will not only tell you verbatim what it found (or not found) but will also set different return codes.
So if you want to rely on these codes instead of the messages just redirect the script's stdout to /dev/null (or to a logfile, if desired).

Adjust the variables according to your needs.

L1=$(grep -n "$STRING1" $FILE |cut -f1 -d":")
if [[ ! -z $L1 ]] ; then
 L2=$(grep -n "$STRING2" $FILE |cut -f1 -d":")
   if [[ ! -z $L2 ]] ; then
     if [[ $(($L2 - $L1)) -eq $DISTANCE ]] ; then
       echo "SUCCESS! $STRING1 found at line $L1, $STRING2 found at line $L2"
       else echo "$STRING1 ($L1) and $STRING2 ($L2) found, but distance is not $DISTANCE lines!"
     else echo "$STRING1 found, but $STRING2 not found!"
   else echo "$STRING1 not found!"
exit $RC

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Author Closing Comment

ID: 36582396
Thanks.  I'll give it a try.

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