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sql left and charindexfunction

Posted on 2011-09-20
3
225 Views
Last Modified: 2012-05-12
Can anyone please tell why this is erroring out

select            
case  
when isnumeric(left('2022AVEQENSLEY',case when charindex(char(32),'2022AVEQENSLEY')
            =0 then 2
            else charindex(char(32),'2022AVEQENSLEY') end -1)) = 1
then left('2022AVEQENSLEY',charindex(char(32),'2022AVEQENSLEY')-1)
else replace(replace('2022AVEQENSLEY',char(32),''),'.','')
end
      
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Question by:baylar
3 Comments
 
LVL 32

Expert Comment

by:ewangoya
ID: 36571124

This returns 0
charindex(char(32),'2022AVEQENSLEY')

Then you actually reduce it by -1
else charindex(char(32),'2022AVEQENSLEY') end -1))

You can not pass -1 to CHARINDEX function
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LVL 29

Accepted Solution

by:
QPR earned 500 total points
ID: 36571125
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Author Closing Comment

by:baylar
ID: 36571246
Awesome works the way I want.
Thanks
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